Problem 1
Question
Write balanced equations for the following half-reactions. Specify whether each is an oxidation or reduction. (a) \(\mathrm{Cr}(\mathrm{s}) \rightarrow \mathrm{Cr}^{3+}(\mathrm{aq})\) (in acid) (b) \(\mathrm{AsH}_{3}(\mathrm{g}) \rightarrow \mathrm{As}(\mathrm{s})\) (in acid) (c) \(\mathrm{VO}_{3}^{-}(\mathrm{aq}) \rightarrow \mathrm{V}^{2+}(\mathrm{aq})\) (in acid) (d) \(\mathrm{Ag}(\mathrm{s}) \rightarrow \mathrm{Ag}_{2} \mathrm{O}(\mathrm{s})\) (in base)
Step-by-Step Solution
Verified Answer
(a) Oxidation, (b) Oxidation, (c) Reduction, (d) Oxidation.
1Step 1: Understand Oxidation and Reduction
Oxidation involves the loss of electrons and increase in oxidation state, while reduction involves the gain of electrons and decrease in oxidation state. In acid or base, the balancing includes atoms and charges, often involving protons (H) or hydroxide ions (OH).
2Step 2: Balance Chromium Reaction (a)
Begin with the reaction \( \mathrm{Cr}(\mathrm{s}) \rightarrow \mathrm{Cr}^{3+}(\mathrm{aq}) \). Chromium goes from 0 to +3 oxidation state, losing 3 electrons. The balanced equation in acidic solution is:1. Write the skeleton reaction: \( \mathrm{Cr} \rightarrow \mathrm{Cr}^{3+} \).2. Balance chromium atoms: Already balanced.3. Balance electrons: Add 3 electrons to the products side: \( \mathrm{Cr} \rightarrow \mathrm{Cr}^{3+} + 3e^- \).4. Identify: This is an oxidation reaction.
3Step 3: Balance Arsenic Reaction (b)
Consider \( \mathrm{AsH}_{3}(\mathrm{g}) \rightarrow \mathrm{As}(\mathrm{s}) \). Arsenic goes from -3 to 0 oxidation state, losing 3 electrons. In acidic media:1. Write the skeleton reaction: \( \mathrm{AsH}_3 \rightarrow \mathrm{As} \).2. Balance arsenic: Already balanced.3. Balance electrons: Add 3 electrons to the products side: \( \mathrm{AsH}_3 \rightarrow \mathrm{As} + 3H^+ + 3e^- \).4. Identify: This is an oxidation reaction.
4Step 4: Balance Vanadium Reaction (c)
The reaction is \( \mathrm{VO}_{3}^{-}(\mathrm{aq}) \rightarrow \mathrm{V}^{2+}(\mathrm{aq}) \). Vanadium goes from +5 to +2, gaining 3 electrons. Balance in acid:1. Write the skeleton reaction: \( \mathrm{VO}_{3}^{-} \rightarrow \mathrm{V}^{2+} \).2. Add 3 electrons to the reactants: \( \mathrm{VO}_{3}^{-} + 3e^- \rightarrow \mathrm{V}^{2+} \).3. Balance oxygen with water, \( 3H_2O \) added to products: \( \mathrm{VO}_{3}^{-} + 3e^- \rightarrow \mathrm{V}^{2+} + 3H_2O \).4. Balance hydrogen with protons, \( 6H^+ \) added to reactants: \( \mathrm{VO}_{3}^{-} + 3e^- + 6H^+ \rightarrow \mathrm{V}^{2+} + 3H_2O \).5. Identify: This is a reduction reaction.
5Step 5: Balance Silver Reaction (d)
For \( \mathrm{Ag}(\mathrm{s}) \rightarrow \mathrm{Ag}_{2}\mathrm{O}(\mathrm{s}) \). Silver goes from 0 to +1 in \( \mathrm{Ag}_2\mathrm{O} \). Balance in basic solution:1. Write the skeleton reaction: \( 2\mathrm{Ag} \rightarrow \mathrm{Ag}_{2}\mathrm{O} \).2. Add 2 OH- to products for charge balance: \( 2\mathrm{Ag} + 2OH^- \rightarrow \mathrm{Ag}_2\mathrm{O} \).3. Add one water molecule to reactants: \( 2\mathrm{Ag} + 2OH^- \rightarrow \mathrm{Ag}_2\mathrm{O} + H_2O \).4. Identify: This is an oxidation reaction.
Key Concepts
OxidationReductionHalf-ReactionsBalancing Equations
Oxidation
Oxidation occurs when a chemical species loses electrons, leading to an increase in its oxidation state. Imagine oxidation as a process where an element gives away electrons, much like donating energy.
In chemical reactions, recognizing oxidation means identifying the species that is losing electrons. This can be seen as an element's oxidation number increasing in the reaction.
For example, in the reaction
Similarly, in the reaction
In chemical reactions, recognizing oxidation means identifying the species that is losing electrons. This can be seen as an element's oxidation number increasing in the reaction.
For example, in the reaction
- \( ext{Cr} ightarrow ext{Cr}^{3+} + 3e^- \)
Similarly, in the reaction
- \( ext{AsH}_3 ightarrow ext{As} + 3H^+ + 3e^- \)
Reduction
Reduction is the opposite of oxidation. It involves the gain of electrons, leading to a decrease in oxidation state. Think of reduction as receiving electrons.
Recognizing reduction in a reaction involves identifying the species that is gaining electrons, often indicated by a decrease in oxidation number.
For instance, in the reaction:
Recognizing reduction in a reaction involves identifying the species that is gaining electrons, often indicated by a decrease in oxidation number.
For instance, in the reaction:
- \( ext{VO}_{3}^{-} + 3e^- + 6H^+ ightarrow ext{V}^{2+} + 3H_2O \)
Half-Reactions
Half-reactions are used to clearly show the electron transfer process in redox reactions. They break down the overall redox reaction into two simpler parts: oxidation and reduction.
- Oxidation half-reaction: Details the loss of electrons by an element or compound.
- Reduction half-reaction: Shows the gain of electrons.
- \( ext{Cr} ightarrow ext{Cr}^{3+} + 3e^- \)
- \( ext{VO}_{3}^{-} + 3e^- + 6H^+ ightarrow ext{V}^{2+} + 3H_2O \)
Balancing Equations
Balancing redox equations ensures the conservation of mass and charge, critical for correctly representing the reaction. It involves adjusting coefficients to have the same number of each type of atom and total charge on both sides of the equation.
In acidic solutions, often
Consider balancing the silver reaction:
In acidic solutions, often
- H⁺ ions
- Water molecules
- OH⁻ ions
- Water molecules
Consider balancing the silver reaction:
- \( 2 ext{Ag} + 2OH^- ightarrow ext{Ag}_2 ext{O} + H_2O \)
Other exercises in this chapter
Problem 2
Write balanced equations for the following half-reactions. Specify whether each is an oxidation or reduction. (a) \(\mathrm{H}_{2} \mathrm{O}_{2}(\mathrm{aq}) \
View solution Problem 3
Balance the following redox equations. All occur in acid solution. $$\text { (a) } \mathrm{Ag}(\mathrm{s})+\mathrm{NO}_{3}^{-}(\mathrm{aq}) \rightarrow \mathrm{
View solution Problem 4
Balance the following redox equations. All occur in acid solution. (a) \(\operatorname{Sn}(\mathrm{s})+\mathrm{H}^{+}(\mathrm{aq}) \rightarrow \mathrm{Sn}^{2+}(
View solution