Problem 1
Question
Verify that the given ordered triple is a solution of the system. Do not use a calculator. $$\begin{aligned} (-3,6,1) & \\ 2 x+y-z=&-1 \\ x-y+3 z=&-6 \\ -4 x+y+z=& 19 \end{aligned}$$
Step-by-Step Solution
Verified Answer
The ordered triple \((-3, 6, 1)\) is a solution of the system.
1Step 1: Understand the Problem
We need to verify if the ordered triple \((-3, 6, 1)\) is a solution of the given system of equations. This means substituting \(x = -3\), \(y = 6\), and \(z = 1\) into each equation and checking if all the equations hold true.
2Step 2: Substitute into the First Equation
Substitute \(x = -3\), \(y = 6\), and \(z = 1\) into the first equation: \[2x + y - z = -1\]That gives us:\[2(-3) + 6 - 1 = -1\]Calculate:\[-6 + 6 - 1 = -1\]So the expression simplifies to:\[-1 = -1\] This equation holds true.
3Step 3: Substitute into the Second Equation
Substitute \(x = -3\), \(y = 6\), and \(z = 1\) into the second equation:\[x - y + 3z = -6\]That gives us:\[-3 - 6 + 3(1) = -6\]Calculate:\[-3 - 6 + 3 = -6\]Simplify:\[-6 = -6\] This equation also holds true.
4Step 4: Substitute into the Third Equation
Substitute \(x = -3\), \(y = 6\), and \(z = 1\) into the third equation:\[-4x + y + z = 19\]That gives us:\[-4(-3) + 6 + 1 = 19\]Calculate:\[12 + 6 + 1 = 19\]Simplify:\[19 = 19\] This equation holds true as well.
5Step 5: Conclusion
Since the ordered triple \((-3, 6, 1)\) satisfies all three equations in the system, it is indeed a solution of the system.
Key Concepts
Linear EquationsOrdered TripleSubstitution MethodSolution Verification
Linear Equations
Linear equations form the backbone of algebra. They are equations where each term is either a constant or a product of a constant and a single variable. These are characterized by having the highest degree of the variable as one. Linear equations can be represented in the form:
- Standard form: \(ax + by + cz = d\)
- Slope-intercept form: \(y = mx + c\), mainly for two variables
Ordered Triple
An ordered triple is a set of three numbers that define a point in three-dimensional space. Much like ordered pairs (used in two dimensions), an ordered triple consists of three elements written in a specific order: \((x, y, z)\). For this problem, the ordered triple \((-3, 6, 1)\) represents a potential solution where:
- \(x = -3\)
- \(y = 6\)
- \(z = 1\)
Substitution Method
The substitution method is a technique used to solve systems of equations. It involves solving one of the equations for one variable and then substituting this expression into the other equations. Although substitution here is adapted for verification purposes, it typically follows these steps:
- Solve one equation for one of the variables (e.g., \(x\) in terms of \(y\) and \(z\))
- Use this expression wherever this variable appears in the other equations
- Solve the resulting equations for another variable
Solution Verification
Solution verification is the process of checking whether a proposed solution satisfies all the equations in a system. It's like getting the answer to a test and checking each step to make sure it's correct. For a system with three equations, you must confirm that the ordered triple satisfies all:
- Substitute the triple values into each equation
- Simplify to verify that both sides of the equation are equal
- Document that all equations uphold the integrity of the triple
Other exercises in this chapter
Problem 1
Determine whether A and B are imerses by calculating AB and BA. Do not use a calculator. $$A=\left[\begin{array}{ll} 5 & 7 \\ 2 & 3 \end{array}\right] ; B=\left
View solution Problem 1
Find the dimension of each matrix. Identify any square, column, or rove matrices. Do not use a calculator. $$\left[\begin{array}{rr}-3 & 6 \\\7 & -4\end{array}\
View solution Problem 2
Graph each inequality. $$y \leq-2$$
View solution Problem 2
Determine whether A and B are imerses by calculating AB and BA. Do not use a calculator. $$A=\left[\begin{array}{ll} 2 & 3 \\ 1 & 1 \end{array}\right] ; B=\left
View solution