Problem 1
Question
Two equivalent forms of the Chain Rule for calculating the derivative of \(y=f(g(x))\) are presented in this section. State both forms.
Step-by-Step Solution
Verified Answer
Question: State the two equivalent forms of the Chain Rule used to find the derivative of a composite function y = f(g(x)).
Answer: The two equivalent forms of the Chain Rule are:
1. dy/dx = (dy/du) * (du/dx), where y = f(u) and u = g(x).
2. (dy/dx) = f'(g(x)) * g'(x), where y = f(g(x)).
1Step 1: Form 1: Chain Rule using dy/dx, dy/du, and dx/du
The first form of the Chain Rule uses the derivatives dy/dx, dy/du, and du/dx. If y = f(u) and u = g(x), then the derivative dy/dx can be calculated as:
dy/dx = (dy/du) * (du/dx)
So, we first find the derivative dy/du (with respect to u) and du/dx (with respect to x), and then multiply them together to obtain the overall derivative dy/dx.
2Step 2: Form 2: Chain Rule using f' and g' notation
The second form of the Chain Rule uses the prime notation f'(x) and g'(x) for the derivatives of the functions f and g. If y = f(g(x)), then the derivative dy/dx can be calculated as:
(dy/dx) = f'(g(x)) * g'(x)
In this form, we first find the derivatives f'(x) and g'(x), evaluate f'(g(x)), and then multiply the results together to obtain the overall derivative dy/dx.
Other exercises in this chapter
Problem 1
Use \(x=e^{y}\) to explain why \(\frac{d}{d x}(\ln x)=\frac{1}{x},\) for \(x>0\).
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$$\text { State the derivative formulas for } \sin ^{-1} x, \tan ^{-1} x, \text { and } \sec ^{-1} x$$
View solution Problem 1
How do you find the derivative of the product of two functions that are differentiable at a point?
View solution Problem 1
Explain why \(f^{\prime}(x)\) could be positive or negative at a point where \(f(x) > 0\).
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