Problem 1
Question
The tangent plane at the indicated point \(\left(x_{0}, y_{0}, z_{0}\right)\) exists. Find its equation. $$ f(x, y)=2 x^{3}+y^{2} ;(1,2,6) $$
Step-by-Step Solution
Verified Answer
The equation of the tangent plane is \( z = 6x + 4y - 8 \).
1Step 1: Review the Problem Requirements
We are tasked with finding the equation of the tangent plane to the surface described by the function \( f(x, y) = 2x^3 + y^2 \) at the point \((1, 2, 6)\). We need to use the formula for the tangent plane to a function at a given point.
2Step 2: Understand the Tangent Plane Equation
The equation of the tangent plane to a function \( z = f(x, y) \) at a point \((x_0, y_0, z_0)\) is given by:\[ z = z_0 + f_x(x_0, y_0)(x - x_0) + f_y(x_0, y_0)(y - y_0) \]where \( f_x \) and \( f_y \) are the partial derivatives of \( f \) with respect to \( x \) and \( y \), respectively.
3Step 3: Calculate Partial Derivatives
First, find the partial derivative of \( f(x, y) \) with respect to \( x \):\[ f_x(x, y) = \frac{\partial}{\partial x}(2x^3 + y^2) = 6x^2 \]Next, find the partial derivative of \( f(x, y) \) with respect to \( y \):\[ f_y(x, y) = \frac{\partial}{\partial y}(2x^3 + y^2) = 2y \]
4Step 4: Evaluate Partial Derivatives at (1, 2)
Substitute \( x = 1 \) and \( y = 2 \) into the partial derivatives:\[ f_x(1, 2) = 6(1)^2 = 6 \]\[ f_y(1, 2) = 2(2) = 4 \]
5Step 5: Construct the Tangent Plane Equation
Use the point \((1, 2, 6)\) and the partial derivative values to plug into the tangent plane equation:\[ z = 6 + 6(x - 1) + 4(y - 2) \]Simplify:\[ z = 6 + 6x - 6 + 4y - 8 \]\[ z = 6x + 4y - 8 \]
Key Concepts
Partial DerivativesCalculusMultivariable Functions
Partial Derivatives
Partial derivatives are an important concept in calculus, specifically in dealing with multivariable functions. They represent the rate of change of a function as one variable changes while all other variables are kept constant.
For a function like \( f(x, y) \), which depends on two variables \( x \) and \( y \), you can find its partial derivatives with respect to each variable. This involves differentiating the function with respect to one variable while treating the other variable as a constant.
For a function like \( f(x, y) \), which depends on two variables \( x \) and \( y \), you can find its partial derivatives with respect to each variable. This involves differentiating the function with respect to one variable while treating the other variable as a constant.
- To find the partial derivative \( f_x(x, y) \), differentiate \( f \) with respect to \( x \) and treat \( y \) as a constant.
- Similarly, to find \( f_y(x, y) \), differentiate \( f \) with respect to \( y \), keeping \( x \) constant.
Calculus
Calculus is the branch of mathematics that studies continuous change. It is divided mainly into differential calculus and integral calculus. In differential calculus, we find the derivative, which measures how a function changes as its input changes.
For functions of more than one variable, like \( f(x, y) \), calculus is extended to partial derivatives. These allow us to analyze the change in the function with respect to each variable independently, while others remain fixed.
For functions of more than one variable, like \( f(x, y) \), calculus is extended to partial derivatives. These allow us to analyze the change in the function with respect to each variable independently, while others remain fixed.
- Differential calculus helps to understand the behavior and innermost changes of curves and surfaces.
- It's essential for computing rates of change in various fields, like physics, engineering, and economics.
Multivariable Functions
Multivariable functions are functions that have more than one input variable. For instance, \( f(x, y) \) is a multivariable function with two variables, \( x \) and \( y \). Such functions are used to model scenarios where outcomes depend on multiple factors.
- Understanding multivariable functions is crucial for sciences that deal with systems influenced by multiple changing conditions.
- They commonly appear in physics, economics, and engineering spaces where variables interact in complex ways.
Other exercises in this chapter
Problem 1
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