Problem 1
Question
The inverse sine, inverse cosine, and inverse tangent functions have the followings domains and ranges. (a) The function \(\sin ^{-1}\) has domain _______ and range _______. (b) The function \(\cos ^{-1}\) has domain _______ and range _______. (c) The function \(\tan ^{-1}\) has domain _______ and range _______.
Step-by-Step Solution
Verified Answer
(a) Domain: [-1, 1], Range: [-π/2, π/2]. (b) Domain: [-1, 1], Range: [0, π]. (c) Domain: (-∞, ∞), Range: (-π/2, π/2).
1Step 1: Explaining Inverse Sine Function
The inverse sine function, denoted as \( \sin^{-1} \), is the function that "undoes" the sine function over a specific domain and range. The domain of \( \sin^{-1} \) is the set of values for which the function is defined, and this is the interval \([-1, 1]\). The range is the set of output values, which corresponds to the angles, and for \( \sin^{-1} \), this is \([-\pi/2, \pi/2]\).
2Step 2: Explaining Inverse Cosine Function
The inverse cosine function, represented by \( \cos^{-1} \), is defined similarly, but for the cosine function. The domain of \( \cos^{-1} \) is also \([-1, 1]\), as it only takes values within this interval. The range is different; the outputs are angles between \([0, \pi]\).
3Step 3: Explaining Inverse Tangent Function
The inverse tangent function, denoted as \( \tan^{-1} \), works with the tangent function's domain and range. Unlike the other two, the domain of \( \tan^{-1} \) is all real numbers, \(( -\infty, \infty )\), because tangent can take any real number as an input. Its range is \((-\pi/2, \pi/2)\), the set of angles \(\theta\) whose tangent values it returns.
Key Concepts
Domain and RangeInverse Sine FunctionInverse Cosine FunctionInverse Tangent Function
Domain and Range
Understanding the domain and range of inverse trigonometric functions is crucial for working with these functions effectively. The domain is the set of all possible input values for which the function is defined. The range is the set of possible output values the function can produce.
For inverse trigonometric functions:
For inverse trigonometric functions:
- Domain represents the set of values the original trigonometric function can never exceed.
- Range identifies the angles or results you will obtain from the inverse function.
Inverse Sine Function
The inverse sine function, represented as \( \sin^{-1} \) or \( \arcsin \), is used to find an angle whose sine value gives a specific number.
In terms of domain and range:
In terms of domain and range:
- The domain of \( \sin^{-1} \) is \([-1, 1]\). This is because no sine of a real angle can be more than 1 or less than -1.
- The range of \( \sin^{-1} \) is \([-\pi/2, \pi/2]\). This is because the inverse sine covers the entire first and fourth quadrants.
Inverse Cosine Function
The inverse cosine function, denoted as \( \cos^{-1} \) or \( \arccos \), helps find an angle whose cosine equals a given number.
For the inverse cosine function:
For the inverse cosine function:
- The domain is \([-1, 1]\). Like sine, cosine values range between -1 and 1.
- The range of \( \cos^{-1} \) is \([0, \pi]\), covering angles in the first and second quadrants.
Inverse Tangent Function
Inverse tangent, labeled as \( \tan^{-1} \) or \( \arctan \), calculates the angle whose tangent results in a specified value.
In terms of domain and range, \( \tan^{-1} \) showcases:
In terms of domain and range, \( \tan^{-1} \) showcases:
- A domain of \(( -\infty, \infty )\). Tangent values are not bounded, which means any real number is a possible input.
- A range of \((-\pi/2, \pi/2)\). This range is based on the fact that tangent functions repeat every \(\pi\) radians, but for \( \tan^{-1} \), it focuses on angles from the first and fourth quadrants.
Other exercises in this chapter
Problem 1
For triangle \(A B C\) with sides \(a, b,\) and \(c\) the Law of Cosines states \(c^{2}=\) ________________________
View solution Problem 1
If the angle \(\theta\) is in standard position and \(P(x, y)\) is a point on the terminal side of \(\theta\), and \(r\) is the distance from the origin to \(P,
View solution Problem 2
In which of the following cases must the Law of cosines be used to solve a triangle? $$ASA\quad SSS\quad SAS\quad SSA$$
View solution Problem 2
In which of the following cases can we use the Law of Sines to solve a triangle? ASA SSS SAS SSA
View solution