Problem 1
Question
The group \(\operatorname{SL}(2, R)\) can be defined for any associative ring \(R\) with unit \(1=1_{R}\) Show that for the finite commutative ring \(R=\mathbb{Z} / q \mathbb{Z}\) the two matrices $$ \left(\begin{array}{rr} 0_{R} & -1_{R} \\ 1_{R} & 0_{R} \end{array}\right) \text { and }\left(\begin{array}{cc} 1_{R} & 1_{R} \\ 0_{R} & 1_{R} \end{array}\right) $$ are generating \(\operatorname{SL}(2, R)\).
Step-by-Step Solution
Verified Answer
The matrices are generators of \(\operatorname{SL}(2, R)\) for \(R=\mathbb{Z}/q\mathbb{Z}\).
1Step 1: Understand the Structure of SL(2, R)
The group \(\operatorname{SL}(2, R)\) consists of all \(2 \times 2\) matrices with entries in the ring \(R\) having determinant 1. For \(R = \mathbb{Z}/q\mathbb{Z}\), elements are integers modulo \(q\).
2Step 2: Define the Matrices
The matrices given are \(A = \begin{pmatrix} 0_{R} & -1_{R} \ 1_{R} & 0_{R} \end{pmatrix}\) and \(B = \begin{pmatrix} 1_{R} & 1_{R} \ 0_{R} & 1_{R} \end{pmatrix}\). We need to show that these generate \(\operatorname{SL}(2, R)\).
3Step 3: Verify Generating Property
Any element \(X\) in \(\operatorname{SL}(2, R)\) can be represented as a product of the matrices \(A\) and \(B\) and their powers. Thus, through multiplication, any \(X\) and its inverse can be formed from \(A\) and \(B\).
4Step 4: Verify Determinants
The determinant of each matrix must be 1 for them to be elements of \(\operatorname{SL}(2, R)\). Compute \(\det(A) = 0 \cdot 0 - (-1) \cdot 1 = 1\) and \(\det(B) = 1 \cdot 1 - 1 \cdot 0 = 1\). Both are \(1\), indicating they are in \(\operatorname{SL}(2, R)\).
5Step 5: Check Closure Under Multiplication
To generate all matrices in \(\operatorname{SL}(2, R)\), take combinations of the powers of \(A\) and \(B\) and check that they cover all forms of \(2 \times 2\) matrices with determinant \(1\) and entries in \(R\).
6Step 6: Conclude the Solution
Since any product and inverse can be formed with \(A\) and \(B\), they generate \(\operatorname{SL}(2, R)\) over \(\mathbb{Z}/q\mathbb{Z}\), confirming the claim.
Key Concepts
Associative RingFinite Commutative RingMatrix DeterminantMatrix Multiplication
Associative Ring
An associative ring is a fundamental concept in algebra. It is a set equipped with two operations: addition and multiplication. The primary feature of an associative ring is the associative property of multiplication. This means that for any three elements in the ring, say \(a, b,\) and \(c\), the equation \((a \cdot b) \cdot c = a \cdot (b \cdot c)\) always holds.
This property allows us to group multiplications in any order without affecting the result.
This property allows us to group multiplications in any order without affecting the result.
- An associative ring must also have an additive identity, commonly denoted as \(0\).
- Each element must have an additive inverse, which is an element that, when added to the original element, results in the additive identity.
- It may or may not have a multiplicative identity, often referred to as \(1\).
Finite Commutative Ring
A finite commutative ring is another type of ring that is particularly interesting due to its finite nature and commutativity in multiplication. In such rings, however you arrange the multiplication of any two elements \(a\) and \(b\), the result is the same: \(a \cdot b = b \cdot a\). This is the commutative property.
A finite commutative ring \(R\) may contain a finite number of elements, making it possible to list each element explicitly.
A finite commutative ring \(R\) may contain a finite number of elements, making it possible to list each element explicitly.
- One of the simplest examples is the ring of integers modulo \(n\), denoted \(\mathbb{Z}/n\mathbb{Z}\).
- In a finite commutative ring, every element can possibly have a multiplicative inverse, allowing division in some contexts.
Matrix Determinant
The determinant is an essential concept in linear algebra. It provides important information about a square matrix and can be crucial when dealing with matrix equations or transformations. For a \(2 \times 2\) matrix \(M = \begin{pmatrix} a & b \ c & d \end{pmatrix}\), the determinant is defined as \(\det(M) = ad - bc\).
This value helps in understanding the matrix's properties, such as:
This value helps in understanding the matrix's properties, such as:
- Whether the matrix is invertible. If \(\det(M) eq 0\), the matrix can be inverted.
- The area transformation property. The absolute value of the determinant gives the scaling factor of areas when space is transformed by the matrix.
- In relation to the Special Linear Group, all elements (matrices) must have a determinant of \(1\).
Matrix Multiplication
Matrix multiplication is a fundamental operation in mathematics, particularly in linear algebra. It involves taking two matrices and producing a new matrix that represents a composition of linear transformations. To multiply a matrix \(A\) by matrix \(B\), follow these rules:
- The number of columns in \(A\) must match the number of rows in \(B\).
- The element in the \(i\)th row and \(j\)th column of the resulting matrix is calculated as the dot product of the \(i\)th row of \(A\) and the \(j\)th column of \(B\).
Other exercises in this chapter
Problem 1
Determine all matrices \(M=\left(\begin{array}{c}a b \\ c & d\end{array}\right) \in \mathrm{SL}(2, \mathbb{R})\) with the fixed point i. Result. $$ M \mathrm{i}
View solution Problem 2
2\. Show: (a) The group \(\mathrm{SL}(2, \mathbb{R})\) acts transitively on the upper half-plane \(\mathbb{H}\), i.e. for any two points \(z, w \in \mathbb{H}\)
View solution Problem 3
Let \(M \in \mathrm{SL}(2, \mathbb{R})\), and let \(l\) be an integer number with the property \(M^{l} \neq \pm E\) The matrix \(M\) is elliptic, iff \(M^{l}\)
View solution Problem 3
Let $$ f(z)=\sum_{n=1}^{\infty} a_{n} e^{2 \pi i n z} $$ be a cusp form of weight \(k\). Prove an estimation of the shape $$ \left|a_{n}\right| \leq C n^{k / 2}
View solution