Problem 1
Question
The graph of each equation is a parabola. Determine whether the parabola opens upward, downward, to the left, or to the right. Do not graph. $$y=x^{2}-7 x+5$$
Step-by-Step Solution
Verified Answer
The parabola opens upwards.
1Step 1: Identify the Standard Form
First, identify the standard form of the parabola. The given equation is \( y = x^2 - 7x + 5 \). This equation is in the form \( y = ax^2 + bx + c \), which is the standard form for a parabola opening either upwards or downwards.
2Step 2: Determine the Direction of Opening
Check the coefficient \( a \) in the standard form \( y = ax^2 + bx + c \). Here, \( a = 1 \). If \( a > 0 \), the parabola opens upwards. If \( a < 0 \), the parabola opens downwards. Since \( a = 1 \), which is positive, the parabola opens upwards.
Key Concepts
Quadratic EquationParabola Opening DirectionStandard Form of a Parabola
Quadratic Equation
A quadratic equation is a second-degree polynomial equation of the form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants with \( a eq 0 \). This equation forms the basis for understanding parabolas in algebra.
Quadratic equations can have several characteristics, such as:
Solving these equations is crucial in many areas of mathematics and applied sciences as they model a wide variety of physical phenomena.
Quadratic equations can have several characteristics, such as:
- The variable \( x \) is squared, which defines the quadratic nature of the equation.
- The equation can be solved using different methods like factoring, completing the square, or the quadratic formula.
- Solutions to quadratic equations are the x-values where the graph of the equation (parabola) intersects the x-axis, often referred to as roots or solutions.
Solving these equations is crucial in many areas of mathematics and applied sciences as they model a wide variety of physical phenomena.
Parabola Opening Direction
The direction in which a parabola opens is determined by the coefficient of the squared term in its equation. For quadratic equations in the standard form \( y = ax^2 + bx + c \):
This behavior is because the sign of \( a \) determines how the values of \( y \) behave as \( x \) becomes very large or very small.
Upward-opening parabolas have a minimum point called the vertex, whereas downward-opening parabolas have a vertex that represents their maximum point. Comprehending the opening direction is helpful for sketching the graph without plotting multiple points.
- If the coefficient \( a \) of \( x^2 \) is positive, the parabola opens upward.
- If the coefficient \( a \) is negative, the parabola opens downward.
This behavior is because the sign of \( a \) determines how the values of \( y \) behave as \( x \) becomes very large or very small.
Upward-opening parabolas have a minimum point called the vertex, whereas downward-opening parabolas have a vertex that represents their maximum point. Comprehending the opening direction is helpful for sketching the graph without plotting multiple points.
Standard Form of a Parabola
The standard form of a parabola concerning quadratic equations is expressed as \( y = ax^2 + bx + c \). This form is a simple representation that helps identify many characteristics of the parabola effortlessly.
Characteristics of this form of a parabola include:
Recognizing the standard form allows for easy transitions to other forms such as vertex form, which can further illuminate the properties of a parabola.
Characteristics of this form of a parabola include:
- \( a \): Coefficient that defines the direction of opening and width of the parabola.
- \( b \): Influences the position of the vertex along the x-axis.
- \( c \): Represents the y-intercept, the point where the parabola crosses the y-axis.
Recognizing the standard form allows for easy transitions to other forms such as vertex form, which can further illuminate the properties of a parabola.
Other exercises in this chapter
Problem 1
Solve each nonlinear system of equations for real solutions. $$ \left\\{\begin{aligned} x^{2}+y^{2} &=25 \\ 4 x+3 y &=0 \end{aligned}\right. $$
View solution Problem 1
Identify the graph of each equation as an ellipse or a hyperbola. Do not graph. \(\frac{x^{2}}{16}+\frac{y^{2}}{4}=1\)
View solution Problem 2
Solve each nonlinear system of equations for real solutions. $$ \left\\{\begin{aligned} x^{2}+y^{2} &=25 \\ 3 x+4 y &=0 \end{aligned}\right. $$
View solution Problem 2
Graph each inequality. See Examples 1 and \(2 .\) $$ y
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