Problem 1
Question
The average of \(n\) numbers \(x_{1}, x_{2}, x_{3}, \ldots, x_{n}\) is \(M .\) If \(x_{n}\) is replaced by \(x^{\prime}\), then new average is (A) \(M-x_{n}+x^{\prime}\) (B) \(\frac{n M-x_{n}+x^{\prime}}{n}\) (C) \(\frac{(n-1) M+x^{\prime}}{m}\) (D) \(\frac{M-x_{n}+x^{\prime}}{n}\)
Step-by-Step Solution
Verified Answer
The correct answer is (B) \(\frac{nM-x_{n}+x^{\prime}}{n}\).
1Step 1: Understand the Problem
We want to find the new average when the last number in a sequence is replaced with a different number. We are comparing different mathematical expressions to find the correct new average formula.
2Step 2: Express the Initial Average
The average of the initial set of numbers is given by the formula \(M = \frac{x_1 + x_2 + x_3 + \cdots + x_n}{n}\).
3Step 3: Calculate the Total Sum Using the Average
Rearrange the formula for the average to find the total sum: \(nM = x_1 + x_2 + x_3 + \cdots + x_n\).
4Step 4: Substitute the Number
To find the new sum when \(x_n\) is replaced by \(x'\), use \(nM - x_n + x'\).
5Step 5: Calculate the New Average
Divide the new total sum by \(n\) to find the new average: \( \frac{nM - x_n + x'}{n} \).
6Step 6: Compare to the Given Options
Compare \( \frac{nM - x_n + x'}{n} \) with the given options: **(A)** \(M - x_n + x'\); **(B)** \(\frac{nM - x_n + x'}{n}\); **(C)** \(\frac{(n-1)M + x'}{m}\); **(D)** \(\frac{M - x_n + x'}{n}\). The matching formula is **(B)**.
Key Concepts
Sequence of NumbersNew Average CalculationReplacement of a Number
Sequence of Numbers
In mathematics, a sequence of numbers is simply an ordered list of numbers. These numbers follow a specific pattern or rule. For instance, the sequence \( x_1, x_2, x_3, \ldots, x_n \) indicates that each number in the sequence is represented by \( x \) with a subscript indicating its position in the sequence. In particular, this exercise involves \( n \) numbers, which means our sequence has exactly \( n \) terms.
The average, or the mean, of this sequence is calculated by summing all these numbers and then dividing by the number of terms, \( n \). This is given by the formula:
The average, or the mean, of this sequence is calculated by summing all these numbers and then dividing by the number of terms, \( n \). This is given by the formula:
- \( M = \frac{x_1 + x_2 + x_3 + \cdots + x_n}{n} \).
New Average Calculation
Calculating a new average after changing an element in the sequence requires understanding how the previous average was affected by the sequence's elements. When one number in a sequence is replaced, it affects the total sum of the sequence, hence altering the average.
Initially, the total sum of the sequence was calculated using:
Initially, the total sum of the sequence was calculated using:
- \( nM = x_1 + x_2 + x_3 + \cdots + x_n \).
- \( nM - x_n + x' \).
- \( \frac{nM - x_n + x'}{n} \).
Replacement of a Number
Replacing a number in a sequence significantly impacts the average calculation. It is important to handle this change methodically to ensure the new average is precise.
In the given exercise, we're dealing with replacing \( x_n \) by \( x' \). This action directly influences the sum of the sequence, as the removed number \( x_n \) is no longer contributing to the sum, and the new number \( x' \) takes its place.
Here's the step-by-step approach for handling such a replacement:
In the given exercise, we're dealing with replacing \( x_n \) by \( x' \). This action directly influences the sum of the sequence, as the removed number \( x_n \) is no longer contributing to the sum, and the new number \( x' \) takes its place.
Here's the step-by-step approach for handling such a replacement:
- Identify the initial sum of the sequence based on the average: \( nM = x_1 + x_2 + x_3 + \cdots + x_n \).
- Subtract the value being replaced, \( x_n \), from this sum.
- Add the new number, \( x' \), to this result to find the updated total sum.
- Finally, calculate the new average using this adjusted sum: \( \frac{nM - x_n + x'}{n} \).
Other exercises in this chapter
Problem 2
The standard deviation of 25 numbers is \(40 .\) If each of the numbers is increased by 5, then the new standard deviation will be (A) 40 (B) 45 (C) \(40+\frac{
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The mean weight of 9 items is 51 . If one more item is added to the series the mean becomes 16 . The value of the 10 th item is (A) 35 (B) 30 (C) 25 (D) 20
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The mean and S.D. of the marks of 200 candidates were found to be 40 and 15 respectively. Later, it was discovered that a score of 40 was wrongly read as 50 . T
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