Problem 1
Question
The angle of elevation of the top of a vertical pole when observed from each vertex of a regular hexagon is \(\frac{\pi}{3}\). If the area of the circle circumscribing the hexagon be \(A\) sq. metre, then the area of the hexagon is (A) \(\frac{3 \sqrt{3}}{2} A\) sq. metres (B) \(\frac{3 \sqrt{3}}{\pi} A\) sq. metres (C) \(\frac{3 \sqrt{3}}{2} \frac{A}{\pi}\) sq. metres (D) none of these
Step-by-Step Solution
Verified Answer
Option C: \(\frac{3\sqrt{3}}{2} \frac{A}{\pi}\) sq. metres.
1Step 1: Understanding the Problem
We know that the angle of elevation from any vertex of the hexagon to the top of the pole is \(\frac{\pi}{3}\). This implies that the altitude of the pole and the distance from any vertex to the base of the pole forms an equilateral triangle. We need to find the area of the regular hexagon when given the area of the circumscribed circle.
2Step 2: Determine Key Relationships
The regular hexagon can be divided into 6 equilateral triangles. If \(s\) is the side length of each triangle, then the radius \(R\) of the circumscribed circle is equal to \(s\). The area \(A\) of the circle is \(A = \pi R^2\).
3Step 3: Calculate Side Length of Hexagon
Since \(R = s\), and the radius equals the side length of the hexagon, we have \(R^2 = s^2\).
4Step 4: Find Hexagon Area in terms of R
The area of the regular hexagon is given by \( \frac{3\sqrt{3}}{2}s^2 \). Replacing \(s^2\) with \(R^2\), the expression becomes \( \frac{3\sqrt{3}}{2}R^2 \). Since \(R^2 = \frac{A}{\pi}\), we have the hexagon's area as \( \frac{3\sqrt{3}}{2} \times \frac{A}{\pi} \).
5Step 5: Select the Correct Option
The expression for the area of the hexagon is \( \frac{3\sqrt{3}}{2} \times \frac{A}{\pi} \), which corresponds to option (C).
Key Concepts
Regular HexagonAngle of ElevationCircumscribed Circle
Regular Hexagon
A regular hexagon is a polygon with six equal sides and six equal angles. Each interior angle of a regular hexagon is 120 degrees, and each exterior angle is 60 degrees.
One of the unique properties of a regular hexagon is that it can be divided into six equilateral triangles.
This can be easily visualized if you draw straight lines connecting each vertex to the center of the hexagon.
One of the unique properties of a regular hexagon is that it can be divided into six equilateral triangles.
This can be easily visualized if you draw straight lines connecting each vertex to the center of the hexagon.
- The side length of the hexagon is consistent throughout. This means each side measures the same distance.
- Each of the equilateral triangles formed internally will have three angles of 60 degrees.
Angle of Elevation
The concept of the angle of elevation is particularly useful in trigonometry and geometry when dealing with heights and distances. The angle of elevation from a point is the angle formed between the horizontal and the line of sight to a higher point.
In the exercise, each vertex of the hexagon at ground level forms this angle with the top of a vertical pole.
In the exercise, each vertex of the hexagon at ground level forms this angle with the top of a vertical pole.
- The given \angle is \(\frac{\pi}{3}\), which corresponds to 60 degrees.
- This implies that the triangle formed between the pole, a point on the ground, and the base is an equilateral triangle (as \angle equals in all).
Circumscribed Circle
In geometry, a circumscribed circle of a polygon, also known as a circumcircle, is a circle that passes through all the vertices of the polygon.
For regular polygons like a regular hexagon, the circumcircle is particularly symmetrical, and its center coincides with the center of the polygon.
For regular polygons like a regular hexagon, the circumcircle is particularly symmetrical, and its center coincides with the center of the polygon.
- The radius of the circumcircle, often denoted as \(R\), is the distance from the circle's center to any of its vertices.
- In the case of a regular hexagon, this radius is equal to the side length of the hexagon itself.
Other exercises in this chapter
Problem 3
\(A\) and \(B\) are two points in the horizontal plane through \(O\), the foot of pillar \(O P\) of height \(h\), such that \(\Delta A O B=\theta\). If the elev
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A flag is mounted on the semicircular dome of radius \(r .\) The elevation of the top of the flag at any point on the ground is \(30^{\circ}\). Moving \(d\) dis
View solution Problem 5
An observer finds that the angular elevation of a tower is \(A\). On advancing \(3 \mathrm{~m}\) towards the tower the elevation is \(45^{\circ}\) and on advanc
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