Problem 1
Question
$$ \text { Given } f(x)=x^{2} \text { , find } f^{\prime}(0), f^{\prime}(1) \& f^{\prime}(-1) \text { by first principles. }\\{\text { Ans. } 0,2,-2\\} $$
Step-by-Step Solution
Verified Answer
Using the first principle of differentiation, the derivatives of the function \(f(x)=x^{2}\) at \(x=0\), \(x=1\), and \(x=-1\) are \(f^{\prime}(0) = 0\), \(f^{\prime}(1) = 2\), and \(f^{\prime}(-1) = -2\), respectively.
1Step 1: Understanding the First Principle of Differentiation
The first principle of differentiation states that the derivative of a function \(f(x)\) at a point \(x\) is given by: \[ f^{\prime}(x)=\lim_{{h \to 0}}\frac{f(x+h)-f(x)}{h} \]
2Step 2: Substituting the given function into the principle
We substitute \(f(x)=x^{2}\) into the principle of differentiation: \[ f^{\prime}(x) = \lim_{{h \to 0}}\frac{(x+h)^{2} - x^{2}}{h} \] Simplify this equation to get: \[ f^{\prime}(x) = \lim_{{h \to 0}}\frac{x^{2} + 2xh + h^{2} - x^{2}}{h} \] \[ f^{\prime}(x) = \lim_{{h \to 0}}2x + h \]
3Step 3: Calculate \(f^{\prime}(0)\)
Substitute \(x = 0\) into the simplified derivative equation: \[f^{\prime}(0) = 2(0) + 0 = 0 \]
4Step 4: Calculate \(f^{\prime}(1)\)
Substitute \(x = 1\) into the simplified derivative equation: \[f^{\prime}(1) = 2(1) + 0 = 2 \]
5Step 5: Calculate \(f^{\prime}(-1)\)
Substitute \(x = -1\) into the simplified derivative equation: \[f^{\prime}(-1) = 2(-1) + 0 = -2 \]
Key Concepts
First Principle of DifferentiationDerivativeLimit
First Principle of Differentiation
The first principle of differentiation is a cornerstone concept in calculus. It is a method to find the derivative of a function using the limit process. The derivative represents the rate of change of the function at a particular point. To understand the first principle, let's consider any function \(f(x)\). The idea is to look at the change in \(f(x)\) as we make a small change \(h\) to \(x\). We then evaluate whether this change converges to a particular value as \(h\) approaches zero.
The derivative of the function \(f(x)\) at a point \(x\) is mathematically expressed as:
To apply this principle, we can substitute our specific function into this formula and perform limit calculations to extract the derivative.
The derivative of the function \(f(x)\) at a point \(x\) is mathematically expressed as:
- \(f'(x) = \lim_{{h \to 0}} \frac{f(x+h) - f(x)}{h}\)
To apply this principle, we can substitute our specific function into this formula and perform limit calculations to extract the derivative.
Derivative
A derivative is a fundamental concept in calculus that measures how a function changes as its input changes. It's often described as the function's instantaneous rate of change or slope of the tangent line at any point on its graph. For a given function \(f(x)\), its derivative \(f'(x)\) gives us valuable information.
For example, if \(f(x) = x^2\), the derivative \(f'(x)\) tells us how the output \(f(x)\) will change as \(x\) changes. In the exercise solution, we calculate:
For example, if \(f(x) = x^2\), the derivative \(f'(x)\) tells us how the output \(f(x)\) will change as \(x\) changes. In the exercise solution, we calculate:
- At \(x = 0\), \(f'(0) = 0\), implying the function does not change at that point.
- At \(x = 1\), \(f'(1) = 2\), indicating an increase at a constant rate of 2.
- At \(x = -1\), \(f'(-1) = -2\), suggesting a decrease at a rate of 2.
Limit
The concept of a limit is pivotal in calculus, particularly when working with the first principle of differentiation. It analyzes how a function behaves as it approaches a specific point. In the first principle of differentiation, the limit helps us determine the derivative by considering values very close to, but not exactly at, a point.
To calculate the derivative using the first principle, we evaluate the expression \( \lim_{{h \to 0}} \frac{f(x+h) - f(x)}{h}\). Here, \(h\) symbolizes a minute increment or decrement to the variable \(x\).
By observing how \( \frac{f(x+h) - f(x)}{h} \) behaves as \(h\) approaches zero, we're able to calculate the slope of the tangent line to \(f(x)\). The precise "approaching" behavior is at the core of a limit. It allows us to reach the derivative, a concept giving boundless applications in physics, engineering, and beyond for continuous functions.
To calculate the derivative using the first principle, we evaluate the expression \( \lim_{{h \to 0}} \frac{f(x+h) - f(x)}{h}\). Here, \(h\) symbolizes a minute increment or decrement to the variable \(x\).
By observing how \( \frac{f(x+h) - f(x)}{h} \) behaves as \(h\) approaches zero, we're able to calculate the slope of the tangent line to \(f(x)\). The precise "approaching" behavior is at the core of a limit. It allows us to reach the derivative, a concept giving boundless applications in physics, engineering, and beyond for continuous functions.
Other exercises in this chapter
Problem 2
$$ \text { Given } \left.f(x)=\sqrt{x} \text { , find } f^{\prime}(0) \& f^{\prime}(1) \text { by first principles. \\{Ans. does not exist, } \frac{1}{2}\right\
View solution Problem 3
$$ \text { Given } \left.f(x)=\sqrt[3]{x} \text { , find } f^{\prime}(0) \text { by first principles. \\{ns. does not exist }\right\\} $$
View solution Problem 4
$$ \text { Given } f(x)=x^{a} \text { , show that } f^{\prime}(0) \text { does not exist if } 0
View solution