Problem 1
Question
Suppose that \(\lim _{(x, y \rightarrow(3,1)} f(x, y)=6 .\) What can you say about the value of \(f(3,1) ?\) What if \(f\) is continuous?
Step-by-Step Solution
Verified Answer
If \( f \) is continuous, \( f(3,1) = 6 \); otherwise, \( f(3,1) \) can be any value.
1Step 1: Understanding Limits
We are given that \( \lim_{(x, y) \to (3,1)} f(x, y) = 6 \). This means as \( (x, y) \) approaches \( (3,1) \), the function \( f(x, y) \) approaches the value 6. However, this does not directly tell us the value of \( f(3,1) \).
2Step 2: Considering Discontinuity
If the function \( f \) might be discontinuous at \( (3,1) \), there is no requirement for \( f(3,1) \) to equal the limit \( 6 \). Thus, \( f(3, 1) \) could be any value if \( f \) is not continuous.
3Step 3: Analyzing Continuity
If the function \( f \) is continuous at the point \( (3,1) \), then by the definition of continuity, \( f(3,1) \) must equal \( \lim_{(x, y) \to (3,1)} f(x, y) = 6 \). Thus, if \( f \) is continuous, \( f(3,1) = 6 \).
Key Concepts
Understanding Continuity in CalculusUnpacking DiscontinuityExploring Multivariable Functions
Understanding Continuity in Calculus
In calculus, the concept of continuity plays a vital role. A function is considered continuous at a point if, intuitively speaking, you can draw the function's graph at that point without lifting your pencil. More formally, a function \( f(x, y) \) is continuous at a point \((a, b)\) if
- \( \lim_{(x, y) \to (a, b)} f(x, y) \) exists,
- \( f(a, b) \) is defined, and
- \( \lim_{(x, y) \to (a, b)} f(x, y) = f(a, b) \).
Unpacking Discontinuity
Discontinuity in a function occurs when there is an interruption or a sudden change in the function's behavior at a particular point. This often results from the limit of the function not equalling the function's value at that point. When a function \( f(x, y) \) is discontinuous at a point \((a, b)\), one or more of the conditions for continuity fail.
There are different types of discontinuities:
There are different types of discontinuities:
- Jump Discontinuity: The function has a sudden "jump" at the point.
- Infinite Discontinuity: The function's value approaches infinity around the point.
- Removable Discontinuity: The limit exists and the function can be redefined at the point to be continuous.
Exploring Multivariable Functions
Multivariable functions, as the name implies, are functions with more than one input variable. They can be of the form \( f(x, y) \), where both \( x \) and \( y \) contribute to the output. These functions are fundamental in higher-dimensional analysis, allowing us to model complex systems such as physical phenomena and economic models.
The concept of limits for multivariable functions is a key topic in calculus. In these functions, we evaluate how the function behaves as the variables approach certain values from all possible directions. This can be a bit more involved than single-variable limits because the paths of approach are infinite.
The concept of limits for multivariable functions is a key topic in calculus. In these functions, we evaluate how the function behaves as the variables approach certain values from all possible directions. This can be a bit more involved than single-variable limits because the paths of approach are infinite.
- The limit \( \lim_{(x, y) \to (a, b)} f(x, y) \) exists if from whatever direction \((x, y)\) approaches \((a, b)\), \( f(x, y) \) approaches the same value.
- The analysis of multivariable limits is crucial for understanding the function’s continuity or discontinuity at a point.
Other exercises in this chapter
Problem 1
\(1-6\) Use the Chain Rule to find \(d z / d t\) or \(d w / d t\) $$z=x^{2}+y^{2}+x y, \quad x=\sin t, \quad y=e^{t}$$
View solution Problem 1
The temperature \(T\) at a location in the Northern Hemisphere depends on the longitude \(x,\) latitude \(y,\) and time \(t,\) so we can write \(T=f(x, y, t) .\
View solution Problem 1
I-6 Find an equation of the tangent plane to the given surface at the specified point. $$ z=4 x^{2}-y^{2}+2 y, \quad(-1,2,4) $$
View solution Problem 1
Suppose \((1,1)\) is a critical point of a function \(f\) with contin- uous second derivatives. In each case, what can you say about \(f ?\) $$\begin{array}{ll}
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