Problem 1
Question
Solve the following rational equations. \(\frac{2 x}{5}=\frac{x-14}{6}\)
Step-by-Step Solution
Verified Answer
Answer: The value of x that satisfies the given rational equation is \(x = -10\).
1Step 1: Identify the equation
We are given the rational equation:
\(\frac{2x}{5} = \frac{x-14}{6}\)
2Step 2: Clear the denominators
In order to clear the denominators, we need to find the least common multiple (LCM) of the two denominators 5 and 6. In this case, the LCM of 5 and 6 is 30. Now, we'll multiply both sides of the equation by the LCM:
\(30 \cdot \frac{2x}{5} = 30 \cdot \frac{x-14}{6}\)
3Step 3: Simplify the equation
After multiplying both sides by 30, we can simplify the equation:
\((30/5) \cdot 2x = (30/6) \cdot (x-14)\)
\(12x = 5(x-14)\)
4Step 4: Distribute the values
Now we will distribute the 5 to both terms inside the parenthesis:
\(12x = 5x - 70\)
5Step 5: Isolate x
To isolate x, we will subtract the 5x from both sides:
\(7x = -70\)
Now, divide both sides by 7 to get the final x-value:
\(x = -10\)
So, the solution to the rational equation \(\frac{2x}{5} = \frac{x-14}{6}\) is \(x = -10\).
Key Concepts
Understanding Least Common Multiple (LCM)Isolating the VariableSimplifying Equations
Understanding Least Common Multiple (LCM)
When solving rational equations, one key step is to clear the denominators. To do this, we find the Least Common Multiple (LCM) of the denominators. The LCM is the smallest number that both denominators can divide without a remainder. For example, in the equation \(\frac{2x}{5} = \frac{x-14}{6}\), the denominators are 5 and 6.
To find the LCM of 5 and 6:
To find the LCM of 5 and 6:
- List the multiples of each number:
- Multiples of 5: 5, 10, 15, 20, 25, 30, ...
- Multiples of 6: 6, 12, 18, 24, 30, ...
- The smallest common multiple is 30.
Isolating the Variable
Once the equation is free of fractions, the next step is to isolate the variable, which means getting the variable by itself on one side of the equation. In the example \(12x = 5(x-14)\), we first distribute the 5 to the terms inside the parenthesis.
This gives us:
This gives us:
- \(12x = 5x - 70\)
- \(12x - 5x = -70\)
- \(7x = -70\)
- \(x = -10\)
Simplifying Equations
Simplifying equations involves making them as straightforward as possible, often by combining like terms and eliminating complex fractions. After using the LCM to clear fractions, we'll apply simplification techniques.
In our example, we simplified the equation:
Simplification helps to solve equations more easily by reducing clutter and focusing only on the necessary steps.
In our example, we simplified the equation:
- After multiplying both sides by 30, we ended up with \(12x = 5(x-14)\).
- Distribution led to \(12x = 5x - 70\).
- Subtract \(5x\) from \(12x\) to simplify the left side.
- Combine to get \(7x = -70\).
Simplification helps to solve equations more easily by reducing clutter and focusing only on the necessary steps.
Other exercises in this chapter
Problem 1
Use the combine-divide method to simplify each expression. $$ \frac{\frac{27 x^{2}}{6}}{\frac{15 x^{3}}{8}} $$
View solution Problem 1
The same number is added to the numerator and denominator of the fraction \(\frac{4}{9} .\) The result is \(\frac{2}{3} .\) What is the number that is added? St
View solution Problem 1
Find the domain of each of the following rational expressions. $$ \frac{2}{x-7} $$
View solution Problem 1
Perform each multiplication. $$ \frac{5}{3} \cdot \frac{6}{7} $$
View solution