Problem 1
Question
Since \(\sum_{2}^{\infty} 1 /(n \log n)\) diverges, \(\lim _{n \rightarrow \infty} \sum_{2}^{n} 1 /(k \log k)=\infty .\) How many terms must be taken before the partial sums exceed \(10 ?\)
Step-by-Step Solution
Verified Answer
By iteratively summing the series from 2 to n, the number of terms required for the sum to exceed 10 can be found when the sum first exceeds 10. This will give the answer to how many terms must be taken before the partial sums exceed 10.
1Step 1: Set up the sum formula
We are given the series is \( \sum_{2}^{n} 1 /(k \log k) \) and we need to find n where the sum of the series exceeds 10. This will involve evaluating the sum from k=2 to an increasing n, until the sum exceeds 10.
2Step 2: Iteratively calculate partial sums
Since an explicit formula for the sum of the series is not available, use iteration to calculate the partial sum. This can be done using a loop structure in a program or a spreadsheet.
3Step 3: Identify the term count when sum exceeds 10
Continue the iteration from Step 2 until the partial sum crosses the 10 mark. The value of n at that time gives the number of terms required. Note that the series starts from 2, so when figuring out how many terms there are, remember to subtract 1 from n.
Key Concepts
Partial SumLogarithmic FunctionLimit of a Sequence
Partial Sum
A partial sum is essentially the sum of the first few terms of a series. It gives students a practical approach to understanding how a series behaves. In short, each partial sum is the pointwise addition of terms starting from the first term up to the nth term. When working with a divergent series like \[ S_n = \sum_{k=2}^{n} \frac{1}{k \log k} \] it's necessary to compute partial sums until a stopping criterion is met — for example, exceeding a value like 10 in our exercise. To find out the number of terms needed, students often use computational tools. Here’s why this is important:
- Accumulates Value: The partial sum shows how much of the series total is accumulated with each added term.
- Check for Divergence: Helps determine if a series increases without bound.
- Practical Use: Essential in numerical approximations where precise values are critical.
Logarithmic Function
Logarithmic functions are unique mathematical operations with significant importance in calculus and series. A logarithm essentially represents the power to which we must raise a base (commonly base 10 or base e) to produce a given number. Denoted as \( \log x \), where x is the input number, these functions can transform multiplicative relationships into additive ones.
In the context of series, logarithmic functions are crucial because they help manage growth rates. Taking the expression \( \frac{1}{k \log k} \), we see:
In the context of series, logarithmic functions are crucial because they help manage growth rates. Taking the expression \( \frac{1}{k \log k} \), we see:
- Slow Growth: Logarithms grow slower than polynomials, meaning the terms themselves decrease slowly.
- Divergence Tests: The log function impacts series behavior and convergence, crucial for determining if a series like \( \sum_{2}^{\infty} \frac{1}{n \log n} \) diverges.
- Complexity Management: Reduces larger numbers, aiding in calculation and visualization of real-world data trends.
Limit of a Sequence
Understanding the concept of limits in sequences is vital, particularly when exploring series behavior. A limit investigates what happens to a sequence as the number of terms goes to infinity. In mathematics, a sequence's limit \( L \) exists if for any tiny number \( \epsilon \), we find a point \( N \) beyond which all terms remain close to \( L \).
For a divergent series like our example, the partial sums approach infinity, indicating no finite limit. Here's what to note:
For a divergent series like our example, the partial sums approach infinity, indicating no finite limit. Here's what to note:
- Approaching Infinity: If partial sums continue to increase indefinitely (crossing values like 10), the sequence diverges.
- Determining Terms: Identifying the term count before exceeding certain partial sums helps in practical calculations.
- Conceptual Purity: Mathematicians seek limits for insights into convergence or divergence, impacting series analysis and functional behavior.
Other exercises in this chapter
Problem 1
Investigate the convergence of the following series: (a) \(\frac{1}{3}+\frac{2}{6}+\frac{3}{11}+\frac{4}{18}+\frac{5}{27}+\cdots\) (b) \(\frac{1}{2}-\frac{2}{20
View solution Problem 2
Form the Cauchy product of the following series: $$ \begin{aligned} &1+2+4+8+16+32+\cdots \\ &1-1+1-1+1-1+1-1+\cdots \end{aligned} $$ and find a formula for the
View solution Problem 2
Show that if \(\sum a_{n}\) converges, then \(\sum_{N}^{\infty} a_{n} \rightarrow 0\) as \(N \rightarrow \infty\)
View solution