Problem 1
Question
Sasha said that \(\sin \theta+\cos \theta=2\) has no solution. Do you agree with Sasha? Explain why or why not.
Step-by-Step Solution
Verified Answer
Yes, I agree with Sasha. The equation has no solution because \(\sin \theta\) and \(\cos \theta\) cannot both be 1 simultaneously.
1Step 1: Understanding the Trigonometric Identity
The given equation is \( \sin \theta + \cos \theta = 2 \). We know that the sine and cosine functions range from \(-1\) to \(1\) for all real numbers \(\theta\). Thus, the maximum value that \(\sin \theta + \cos \theta\) can achieve is \(1 + 1 = 2\).
2Step 2: Assessing the Possibility
For \(\sin \theta + \cos \theta\) to equal \(2\), both \(\sin \theta\) and \(\cos \theta\) must simultaneously equal \(1\). However, \(\sin \theta = 1\) implies \(\theta = \frac{\pi}{2} + 2k\pi\), and \(\cos \theta = 1\) implies \(\theta = 2m\pi\), where \(k, m\) are integers. These two conditions cannot be satisfied by the same \(\theta\).
3Step 3: Conclusion Based on Analysis
Since \(\sin \theta = 1\) cannot occur at the same \(\theta\) as \(\cos \theta = 1\), the sum \(\sin \theta + \cos \theta = 2\) is not possible. Thus, the equation \(\sin \theta + \cos \theta = 2\) has no solution.
Key Concepts
Sine FunctionCosine FunctionTrigonometric Functions Range
Sine Function
The sine function is a fundamental component of trigonometry that describes the ratio of the length of the opposite side to the length of the hypotenuse in a right triangle. The function is periodic, meaning it repeats values in cycles. The values of the sine function range between
- -1 and 1.
- The sine of \( heta \) is maximum, equal to \( 1 \), when \( heta \) is \( \frac{\pi}{2} + 2k\pi \), where \( k \) is an integer.
- The sine of \( heta \) is minimum, equal to \( -1 \), when \( \theta \) is \( \frac{3\pi}{2} + 2k\pi \).
Cosine Function
Cosine, like the sine function, is a key trigonometric function that measures the ratio of the adjacent side to the hypotenuse of a right triangle. Cosine is also periodic and spans the same range as sine: it fluctuates between
- -1 and 1.
- The cosine of \( \theta \) reaches its maximum at \( 1 \) when \( \theta \) is \( 2m\pi \) where \( m \) is an integer.
- It achieves its minimum value of \( -1 \) at angles \( \pi + 2m\pi \).
Trigonometric Functions Range
The range of trigonometric functions is crucial in understanding what values are achievable by sine, cosine, and other related functions. The primary trigonometric functions—sine and cosine—both range from
- -1 to 1.
- This defined range limits the possible outcomes of their sums and differences.
Other exercises in this chapter
Problem 1
Isaiah said that if the equation \(\cos 2 x+2 \cos ^{2} x=2\) is divided by \(2,\) an equivalent equation is \(\cos x+\cos ^{2} x=1 .\) Do you agree with Isaiah
View solution Problem 1
The discriminant of the quadratic equation \(\tan ^{2} \theta+4 \tan \theta+5=0\) is \(-4 .\) Explain why the solution set of this equation is the empty set.
View solution Problem 1
Can the equation \(\tan \theta+\sin \theta \tan \theta=1\) be solved by factoring the left side of the equation? Explain why or why not.
View solution