Problem 1
Question
Let \(G\) be an abelian group. Let \(H=\left\\{x^{2}: x \in G\right\\}\) and \(K=\left\\{x \in G: x^{2}=e\right\\}\). Prove that \(f(x)=x^{2}\) is a homomorphism of \(G\) onto \(H\).
Step-by-Step Solution
Verified Answer
The function \(f(x) = x^2\) is a homomorphism of \(G\) onto \(H\) because it preserves the group operation and maps every element in \(H\).
1Step 1: Define Group Homomorphism
To show that the function \(f(x) = x^2\) is a homomorphism, we need to verify that it preserves the group operation. Specifically, for all elements \(x, y \in G\), the function should satisfy \(f(xy) = f(x)f(y)\).
2Step 2: Verify Homomorphism Property
Evaluate \(f(xy)\): \(f(xy) = (xy)^2\). By using the property of the group \(G\) being abelian (commutative), we have \((xy)^2 = xyxy = x^2y^2\), which is equal to \(f(x)f(y)\). Thus, \(f(xy) = f(x)f(y)\) is satisfied, confirming \(f\) is a homomorphism.
3Step 3: Prove Onto Function
To prove that \(f\) is onto, for each element \(h \in H\), there must exist an \(x \in G\) such that \(f(x) = h\). By definition, every element \(h \in H\) can be written as \(x^2\) for some \(x \in G\) (since \(H = \{x^2: x \in G\}\)). Therefore, \(f(x) = x^2 = h\), showing that \(f\) is onto.
Key Concepts
Abelian GroupGroup HomomorphismCommutative Property
Abelian Group
Abelian groups are a fundamental concept in group theory. These groups are characterized by the fact that their group operation is commutative. This means that for any two elements, say \(a\) and \(b\), in the group \(G\), the operation satisfies \(a \cdot b = b \cdot a\). This property simplifies many mathematical proofs and computations.
An abelian group has the following properties:
An abelian group has the following properties:
- Closure: For any elements \(a\) and \(b\) in the group, the result of the operation \(a \cdot b\) is also an element of the same group.
- Associativity: The group operation is associative. So for elements \(a\), \(b\), and \(c\), \((a \cdot b) \cdot c = a \cdot (b \cdot c)\).
- Identity Element: There exists an element, often denoted by \(e\), such that for all elements \(a\), \(e \cdot a = a \cdot e = a\).
- Inverse Element: For each element \(a\), there is an element \(b\) such that \(a \cdot b = b \cdot a = e\).
- Commutative Property: As mentioned, \(a \cdot b = b \cdot a\) for any \(a\), \(b\) in the group.
Group Homomorphism
A group homomorphism is a map between two groups that preserves the structure of the groups. This means that when the group operation is applied to any two elements in the first group, the result of mapping them is equivalent to mapping each and then applying the operation in the second group.
For a group homomorphism \(f: G \to H\), where both \(G\) and \(H\) are groups, the following condition must be satisfied:
For a group homomorphism \(f: G \to H\), where both \(G\) and \(H\) are groups, the following condition must be satisfied:
- Operation Preservation: For all \(x, y \in G\), \(f(xy) = f(x)f(y)\).
Commutative Property
The commutative property is crucial in the study of abelian groups and plays a significant role in proving many properties within group theory. This property states that if a group is commutative, also known as abelian, then for any two elements \(a\) and \(b\) in the group, swapping them in any operation does not change the result.
More formally, for a group \(G\), for any elements \(a, b \in G\), the equations \(a \cdot b = b \cdot a\) hold true. This property simplifies the analysis of the structures and transformations within the group. Because of its simplicity, it is one of the defining features of abelian groups.
Here's why the commutative property is important in proving homomorphism, as detailed in the exercise:
More formally, for a group \(G\), for any elements \(a, b \in G\), the equations \(a \cdot b = b \cdot a\) hold true. This property simplifies the analysis of the structures and transformations within the group. Because of its simplicity, it is one of the defining features of abelian groups.
Here's why the commutative property is important in proving homomorphism, as detailed in the exercise:
- When verifying that a function \(f\) is a homomorphism for an abelian group, the commutative property allows the simplification of expressions, which makes it straightforward to verify that the function preserves group operations.
- It also ensures that any transformations or mappings of elements retain their natural order, as stipulated by the group's operation.
Other exercises in this chapter
Problem 1
Let \(G\) and \(H\) be groups. Suppose \(J\) is a normal subgroup of \(G\) and \(K\) is a normal subgroup of \(H\) Show that the function \(f(x, y)=(J x, K y)\)
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The symbol Aut \((G)\) is used to designate the set of all the automorphisms of \(G\). Prove that the set Aut \((G)\), with the operation o of composition, is a
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In each of the following, use the fundamental homomorphism theorem to prove that the two given groups are isomorphic. Then display their tables. $$ \mathbb{Z}_{
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As a provisional definition, let us call a finite abelian group "decomposable" if there are elements \(a_{1}, \ldots, a_{n} \in G\) such that: (D1) For every \(
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