Problem 1
Question
Is \(\sin \theta=\sqrt{1-\cos ^{2} \theta}\) an identity? Explain why or why not.
Step-by-Step Solution
Verified Answer
No, it's not an identity because it ignores the possible negative value of \( \sin \theta \).
1Step 1: Understand the Equation
The equation given is \( \sin \theta = \sqrt{1 - \cos^2 \theta} \). We want to determine whether this equation is an identity. An identity is an equation that is true for all values of the variable (in this case, \( \theta \)).
2Step 2: Use Pythagorean Identity
There is a known trigonometric identity: \( \sin^2 \theta + \cos^2 \theta = 1 \). Rearrange this identity to express \( \sin^2 \theta \) in terms of \( \cos^2 \theta \): \( \sin^2 \theta = 1 - \cos^2 \theta \).
3Step 3: Relate to Given Equation
Notice that if \( \sin^2 \theta = 1 - \cos^2 \theta \), then \( \sin \theta \) should be ±\( \sqrt{1 - \cos^2 \theta} \). The expression \( \sin \theta = \sqrt{1 - \cos^2 \theta} \) ignores the negative root possibility.
4Step 4: Conclusion on the Identity
Since \( \sin \theta \) can be both positive and negative depending on the quadrant in which \( \theta \) is located, the equation \( \sin \theta = \sqrt{1 - \cos^2 \theta} \) is not an identity. It only holds when \( \sin \theta \) is non-negative, which isn't true for all \( \theta \).
Key Concepts
Pythagorean IdentityQuadrants of the Unit CirclePositive and Negative Values of Sine
Pythagorean Identity
Trigonometric identities are equalities that involve trigonometric functions and are true for every value of the occurring variables. One of the fundamental identities is the Pythagorean Identity:
In the context of our original exercise, the identity allows us to transform and analyze or verify other equations, showing whether they hold true over their range. It's a powerful tool for proving other identities or simplifying expressions. Understanding and remembering the Pythagorean Identity is crucial for anyone studying trigonometry.
- \( \sin^2 \theta + \cos^2 \theta = 1 \).
- \( \sin^2 \theta \) as \( 1 - \cos^2 \theta \)
- \( \cos^2 \theta \) as \( 1 - \sin^2 \theta \).
In the context of our original exercise, the identity allows us to transform and analyze or verify other equations, showing whether they hold true over their range. It's a powerful tool for proving other identities or simplifying expressions. Understanding and remembering the Pythagorean Identity is crucial for anyone studying trigonometry.
Quadrants of the Unit Circle
The unit circle is a circle with a radius of one, centered at the origin of a coordinate plane. It plays a vital role in understanding trigonometric functions and their properties. The circle is divided into four quadrants, each with unique properties that influence the sign of trigonometric functions:
This understanding helps explain why \( \sin \theta \) evaluates differently depending on the angle's location on the circle. So, when trying to determine if an equation is an identity, it is essential to consider the quadrant, since the sign of the trigonometric functions can change.
- Quadrant I: Both sine and cosine are positive.
- Quadrant II: Sine is positive, but cosine is negative.
- Quadrant III: Both sine and cosine are negative.
- Quadrant IV: Sine is negative, but cosine is positive.
This understanding helps explain why \( \sin \theta \) evaluates differently depending on the angle's location on the circle. So, when trying to determine if an equation is an identity, it is essential to consider the quadrant, since the sign of the trigonometric functions can change.
Positive and Negative Values of Sine
The sine function, often written as \( \sin \theta \), represents the vertical component of the radius of the unit circle. As you move through different quadrants, the sign of \( \sin \theta \) changes following the properties of these quadrants:
This understanding is crucial because it shows the importance of correcting the equation to \( \sin \theta = \pm \sqrt{1 - \cos^2 \theta} \) to accurately reflect that sine can be both positive and negative, confirming the equation's identity status.
- In Quadrant I (0 to 90 degrees), sine values are positive.
- In Quadrant II (90 to 180 degrees), sine values remain positive.
- In Quadrant III (180 to 270 degrees), sine values become negative.
- In Quadrant IV (270 to 360 degrees), sine values are negative again.
This understanding is crucial because it shows the importance of correcting the equation to \( \sin \theta = \pm \sqrt{1 - \cos^2 \theta} \) to accurately reflect that sine can be both positive and negative, confirming the equation's identity status.
Other exercises in this chapter
Problem 1
Explain why the identity \(\tan (A+B)=\frac{\tan A+\tan B}{1-\tan A \tan B}\) is not valid when \(A\) or \(B\) is equal to \(\frac{\pi}{2}+n \pi\) for any integ
View solution Problem 1
William said that \(\sin (A+B)+\sin (A-B)=\sin 2 A .\) Do you agree with William? Justify your answer.
View solution Problem 1
Maggie said that \(\cos (A+B)+\cos (A-B)=\cos 2 A .\) Do you agree with Maggie? Justify your answer.
View solution Problem 1
Are the equations \(\sin \theta=\cos \left(90^{\circ}-\theta\right)\) and \(\cos \theta=\sin \left(90^{\circ}-\theta\right)\) true for all real numbers or only
View solution