Problem 1
Question
In Problems 1 through 18 , evaluate the integral. \(\int \cos ^{2} x d x\)
Step-by-Step Solution
Verified Answer
\(\frac{x}{2} + \frac{\sin(2x)}{4} + C\)
1Step 1: Substitute \(\cos^{2}(x)\) with \(\frac{1+\cos(2x)}{2}\)
Using the trigonometric power reduction formula, we rewrite \(\cos^{2}(x)\) as \(\frac{1+\cos(2x)}{2}\). So the integral becomes \(\int \frac{1+\cos(2x)}{2} dx \)
2Step 2: Apply the integral of sum rule
The integral of a sum is equal to the sum of integrals. Here, we separate the integral into two parts: \(\int \frac{1}{2} dx + \int \frac{\cos(2x)}{2} dx \)
3Step 3: Evaluate each integral separately
Evaluate each of the two integrals separately. The integral of \(\frac{1}{2}\) is \(\frac{x}{2}\) and for integral of \(\frac{\cos(2x)}{2}\), use u-substitution, let \(u = 2x\) gives \(dx = \frac{du}{2}\). Substituting these into the integral gives \(\int \frac{\cos(u)}{4} du\), which leads to \(\frac{\sin(u)}{4}\), substituting back \(u = 2x\) we get \(\frac{\sin(2x)}{4}\)
4Step 4: Combine the solutions and add the constant of integration C
Finally, combine the solutions of the two integrals and add the constant of integration \(C\) to the result in order to form the most general solution possible. The final result is \(\frac{x}{2} + \frac{\sin(2x)}{4} + C\)
Key Concepts
Integration TechniquesTrigonometric IdentitiesU-Substitution
Integration Techniques
Integration techniques are essential mathematical tools that allow us to find the area under curves described by functions. In calculus, integrals can sometimes appear complex, but with the right approach, they become manageable.
To integrate certain functions, we often break them down using various rules or techniques. For example, the formula for the sum of integrals states:
To integrate certain functions, we often break them down using various rules or techniques. For example, the formula for the sum of integrals states:
- The integral of a sum is the sum of the integrals: \[ \\int (f(x) + g(x)) \, dx = \int f(x) \, dx + \int g(x) \, dx \]
Trigonometric Identities
Trigonometric identities serve as handy tools in calculus, especially when dealing with integrals involving trigonometric functions. In our current problem, we dealt with \( \cos^{2}(x) \), which can be rewritten using a trigonometric identity known as the power reduction formula:
Mastering these identities is crucial, as they enable the transformation of complex trigonometric expressions into simpler forms, ready for integration or differentiation.
- \[ \\cos^{2}(x) = \frac{1 + \cos(2x)}{2} \]
Mastering these identities is crucial, as they enable the transformation of complex trigonometric expressions into simpler forms, ready for integration or differentiation.
U-Substitution
U-substitution is a valuable method for solving integrals, particularly useful when dealing with composite functions. This technique is akin to the chain rule in differentiation but applied in reverse.
Consider the integral involving \( \cos(2x) \). To simplify this, we use u-substitution:
U-substitution simplifies integration by reducing it to a basic form, helping to easily address otherwise complex integral problems.
Consider the integral involving \( \cos(2x) \). To simplify this, we use u-substitution:
- Let \( u = 2x \). Then, \( du = 2 \, dx \) or \( dx = \frac{du}{2} \).
- This transformation changes the integral: \[ \\int \frac{\cos(2x)}{2} \, dx = \int \frac{\cos(u)}{4} \, du \]
U-substitution simplifies integration by reducing it to a basic form, helping to easily address otherwise complex integral problems.
Other exercises in this chapter
Problem 1
In Problems 1 through 5, pinpoint all the improprieties in the integral. If necessary rewrite the integral as a sum of integrals so that each impropriety occurs
View solution Problem 1
Write out the partial fraction decomposition of each rational function. You need not determine the coefficients; just set them up. (a) \(\frac{x^{2}+3}{x(x-1)(x
View solution Problem 2
Evaluate the integrals. $$ \int x \cos x d x $$
View solution Problem 2
Pinpoint all the improprieties in the integral. If necessary rewrite the integral as a sum of integrals so that each impropriety occurs at an endpoint and there
View solution