Problem 1
Question
In Exercises \(1-8,\) use the Ratio Test to determine if each series converges absolutely or diverges. $$\sum_{n=1}^{\infty} \frac{2^{n}}{n !}$$
Step-by-Step Solution
Verified Answer
The series converges absolutely.
1Step 1: Define the general term of the series
The given series is \(\sum_{n=1}^{\infty} \frac{2^{n}}{n !}\). The general term \(a_n\) of the series is \(a_n = \frac{2^n}{n!}\).
2Step 2: Apply the Ratio Test
To apply the Ratio Test, consider \(L = \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right|\). If \(L < 1\), the series converges absolutely. If \(L > 1\), the series diverges. If \(L = 1\), the test is inconclusive.
3Step 3: Calculate the ratio \( \frac{a_{n+1}}{a_n} \)
Compute the next term \(a_{n+1} = \frac{2^{n+1}}{(n+1)!}\). Now find \(\frac{a_{n+1}}{a_n} = \frac{2^{n+1}}{(n+1)!} \cdot \frac{n!}{2^n} = \frac{2 \cdot 2^n \cdot n!}{2^n \cdot (n+1) \cdot n!} = \frac{2}{n+1}\).
4Step 4: Take the limit as \(n\) approaches infinity
Now, calculate \(L = \lim_{n \to \infty} \left| \frac{2}{n+1} \right| = \lim_{n \to \infty} \frac{2}{n+1} = 0\).
5Step 5: Conclusion of the Ratio Test
Since \(L = 0 < 1\), the series \(\sum_{n=1}^{\infty} \frac{2^n}{n!}\) converges absolutely.
Key Concepts
Convergence of SeriesFactorial in SeriesLimit of a Sequence
Convergence of Series
The concept of convergence is crucial in understanding series. When we talk about the convergence of a series, we are interested in understanding whether the sum of its infinite terms approaches a specific value as we continue to add terms.
\[ \sum_{n=1}^{\infty} a_n \]
Key things to remember about convergence include:
\[ \sum_{n=1}^{\infty} a_n \]
Key things to remember about convergence include:
- If the series converges, it means the sequence of partial sums has a finite limit.
- The series diverges if it does not converge, meaning the sum either increases without bound or oscillates.
- The Ratio Test is a popular method for testing convergence, especially for series with factorials or exponential components.
Factorial in Series
Factorials often occur in series, particularly in problems involving permutations, combinations, or any series approximating exponential functions. A factorial, represented by \( n! \), is a product of all positive integers less than or equal to \( n \). For example, \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \).
In terms of series representation:
In terms of series representation:
- Factorials grow very quickly as \( n \) increases, which effectively reduces the size of subsequent terms in a denominator.
- This characteristic is useful in determining convergence, as factorials in the denominator often lead to a series that converges.
- Knowing how factorials interact within a series can simplify calculations using tests like the Ratio Test.
Limit of a Sequence
The limit of a sequence is a foundational concept in calculus and analysis. It tells us about the behavior of a sequence as the index grows indefinitely. In our context with series, understanding limits is essential for applying the Ratio Test.
Here’s what to know:
Here’s what to know:
- A sequence \( \{a_n\} \) converges to a limit \( L \) if, as \( n \to \infty \), \( a_n \) approaches \( L \).
- Determining the limit of the ratio \( \frac{a_{n+1}}{a_n} \) is crucial in the Ratio Test.
- If the limit \( L < 1 \), the original series converges absolutely. If \( L > 1 \), it diverges. If \( L = 1 \), the test is inconclusive.
Other exercises in this chapter
Problem 1
Determine if the alternating series converges or diverges. Some of the series do not satisfy the conditions of the Alternating Series Test. $$ \sum_{n=1}^{\inft
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In Exercises \(1-36\) , (a) find the series' radius and interval of convergence. For what values of \(x\) does the series converge (b) absolutely, (c) condition
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Use the Comparison Test to determine if each series converges or diverges. \begin{equation}\sum_{n=1}^{\infty} \frac{1}{n^{2}+30}\end{equation}
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Use the Integral Test to determine if the series in Exercises \(1-10\) converge or diverge. Be sure to check that the conditions of the Integral Test are satisf
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