Problem 1
Question
In Exercises 1-16, list all square roots of the given number. If the number has no square roots, write “none”. 256
Step-by-Step Solution
Verified Answer
The square roots of 256 are 16 and -16.
1Step 1: Understand the Concept of Square Roots
The square root of a number is a value that, when multiplied by itself, gives the original number. For example, the square root of 9 is 3 because 3 times 3 equals 9. A number can have both positive and negative square roots.
2Step 2: Recall the Calculation of Square Roots
For any number \( x \), the square roots are the solutions to the equation \( x^2 = a \). When \( a \) is a perfect square, \( x \) will have a whole number and its opposite as solutions.
3Step 3: Identify if 256 is a Perfect Square
Identify if 256 can be expressed as the square of an integer. In this case, if a whole number multiplied by itself results in 256.
4Step 4: Calculate the Square Root of 256
Find out what number squared equals 256. Test numbers sequentially: since \(16^2 = 256\), then 16 is a square root.
5Step 5: Account for Negative Square Root
Recall that both positive and negative versions of a number can be square roots. If \( 16^2 = 256 \), then \((-16)^2 = 256\) as well.
6Step 6: List Both Square Roots
Since both positive and negative 16 satisfy the equation, the square roots of 256 are 16 and -16.
Key Concepts
Perfect SquareCalculation of Square RootsPositive Square RootNegative Square Root
Perfect Square
A perfect square is a number that can be expressed as the product of an integer with itself. For example, 256 is a perfect square because it equals 16 times 16.
A number is considered a perfect square if you can find an integer "n" such that \( n^2 = \text{the number} \).
A number is considered a perfect square if you can find an integer "n" such that \( n^2 = \text{the number} \).
- Examples of perfect squares include 1, 4, 9, 16, 25, 36, etc.
- These numbers result from multiplying an integer by itself: \( 1^2 = 1 \), \( 2^2 = 4 \), \( 3^2 = 9 \), and so on.
Calculation of Square Roots
Calculating a square root involves determining which number, when multiplied by itself, equals the original number.
When the original number is a perfect square, its square root will be a whole number.
When the original number is a perfect square, its square root will be a whole number.
- The square root of 256 is 16 because when you multiply 16 by itself (\( 16 \times 16 \)), the result is 256.
- Calculations for non-perfect squares are more complex and may result in decimal values.
Positive Square Root
The positive square root of a perfect square is simply the principal square root of that number. It is typically the non-negative result.
For example, for the number 256, the positive square root is 16 because \( 16^2 = 256 \).
Every positive number greater than zero has a positive square root.
For example, for the number 256, the positive square root is 16 because \( 16^2 = 256 \).
Every positive number greater than zero has a positive square root.
- The symbol used for square root is "\( \sqrt{} \)", so "\( \sqrt{256} \)" equals 16.
- Positive square roots are useful in various calculations where non-negative values are needed.
Negative Square Root
Just as numbers can have positive square roots, they can also have negative square roots. The negative square root of a number is simply the opposite of the positive one.
For the number 256, the negative square root is -16 because \( (-16)^2 = 256 \).
Every positive number has a corresponding negative square root.
For the number 256, the negative square root is -16 because \( (-16)^2 = 256 \).
Every positive number has a corresponding negative square root.
- When you see an expression like "\( x^2 = 256 \)", both \( x = 16 \) and \( x = -16 \) are solutions.
- It's important to remember that squaring any real number – whether positive or negative – results in a non-negative number.
Other exercises in this chapter
Problem 1
In Exercises 1-16, your solutions should include a well-labeled sketch. The length of one leg of a right triangle is 15 meters, and the length of the hypotenuse
View solution Problem 1
In Exercises 1-16, solve the equation. \(5.57 x-2.45 x=5.46\)
View solution Problem 1
In Exercises 1-20, convert the given fraction to a terminating decimal. \(\frac{59}{16}\)
View solution Problem 1
In Exercises 1-16, divide the numbers. \(\frac{39}{52}\)
View solution