Problem 1
Question
Given that \(\cos t=-\frac{2}{5}\) and that \(P(t)\) is a point in the second quadrant, find sin \(t\).
Step-by-Step Solution
Verified Answer
\( \sin t = \frac{\sqrt{21}}{5} \)
1Step 1: Understanding the Problem
We are given that \( \cos t = -\frac{2}{5} \) and the angle \( t \) is located in the second quadrant. We need to find \( \sin t \). Since \( t \) is in the second quadrant, the cosine of \( t \) is negative, and the sine of \( t \) is positive.
2Step 2: Using the Pythagorean Identity
We use the Pythagorean identity: \( \sin^2 t + \cos^2 t = 1 \). Substitute \( \cos t = -\frac{2}{5} \) into the identity to find \( \sin^2 t \).
3Step 3: Plugging Cosine into Identity
Plug \( \cos t = -\frac{2}{5} \) into the identity:\[\sin^2 t + \left(-\frac{2}{5}\right)^2 = 1\]This simplifies to:\[\sin^2 t + \frac{4}{25} = 1\]
4Step 4: Solving for Sine Squared
Subtract \( \frac{4}{25} \) from 1:\[\sin^2 t = 1 - \frac{4}{25} = \frac{25}{25} - \frac{4}{25} = \frac{21}{25}\]
5Step 5: Finding Sine
Taking the square root of both sides gives:\[\sin t = \pm \sqrt{\frac{21}{25}}\]Since \( t \) is in the second quadrant where sine is positive, we choose the positive root:\[\sin t = \sqrt{\frac{21}{25}} = \frac{\sqrt{21}}{5}\]
6Step 6: Conclusion
Given the calculations and the properties of the trigonometric functions in the second quadrant, we confirm that \( \sin t = \frac{\sqrt{21}}{5} \).
Key Concepts
Second QuadrantPythagorean IdentityCosine FunctionSine Function
Second Quadrant
The second quadrant of a coordinate plane is a fascinating area where specific properties of trigonometric functions emerge. It lies between the angles of 90° to 180°, or \(\frac{\pi}{2}\) to \(\pi\) radians. In this quadrant:
- The cosine function is negative because it represents the x-coordinate, which moves to the left of the origin.
- The sine function remains positive as the y-coordinate value extends upward, above the origin.
Pythagorean Identity
The Pythagorean identity is one of trigonometry's cornerstones. It states that for any angle \(t\):\[\sin^2 t + \cos^2 t = 1\]This identity mirrors the Pythagorean theorem, showing how the lengths of the sides of a right triangle relate on a unit circle. By plugging in the known cosine value, you can solve for the sine value, which is exactly what we do here: substitute \(\cos t = -\frac{2}{5}\) into the equation. This simplifies the problem down and allows for solving \(\sin^2 t\). Understanding this identity is essential to mastering trigonometry.
Cosine Function
The cosine function is deeply tied to the x-axis of the coordinate plane. Its values tell us how far left or right a point is on the unit circle:
- In the second quadrant, cosine values are always negative because it relates to the x-coordinate being negative.
- The given value, \(\cos t = -\frac{2}{5}\), tells us that the point is 2/5 units to the left of the circle's radius.
Sine Function
The sine function represents the y-axis component on a unit circle. It measures how far above or below the point is compared to the origin.
- In the second quadrant, the sine of an angle is positive due to it's relation to the upward direction of the y-axis.
- When cosine is known, the sine value can be derived using identities such as the Pythagorean identity: \(\sin^2 t = \frac{21}{25}\).
Other exercises in this chapter
Problem 1
In Problems \(1-6,\) proceed as in Example 2 and reduce the given trigonometric expression to the form \(y=A\) \(\sin (B x+\phi)\). Sketch the graph and give th
View solution Problem 1
In Problems \(1-16\), draw the given angle in standard position. Bear in mind that the lack of a degree symbol \(\left(^{\circ}\right)\) in an angular measureme
View solution Problem 1
Use a sum or difference formula to find the exact value of the given trigonometric function. Do not use a calculator. $$ \cos \frac{\pi}{12} $$
View solution Problem 2
Use a product-to-sum formula in Theorem 4.7 .1 to write the given product as a sum of cosines or a sum of sines. $$ \sin \frac{3 t}{2} \cos \frac{t}{2} $$
View solution