Problem 1
Question
Give the formula of the stable fluoride formed by \(\mathrm{Li}\) \(\mathrm{Be}, \mathrm{B}, \mathrm{C}, \mathrm{N},\) and \(\mathrm{O} .\) For these fluorides, describe the variation in the bonding that occurs as we move from left to right across the period.
Step-by-Step Solution
Verified Answer
The stable fluorides formed by the given elements are Lithium Fluoride (\(LiF\)), Beryllium Fluoride (\(BeF_2\)), Boron Trifluoride (\(BF_3\)), Carbon Tetrafluoride (\(CF_4\)), Nitrogen Trifluoride (\(NF_3\)), and Oxygen Difluoride (\(OF_2\)). The bonding changes from ionic for Lithium and Beryllium (since they are metals) to covalent from Boron to Oxygen (since they are non-metals). The change in bonding nature reflects the different properties of metals and non-metals, and how these properties change as we move from left to right across a period.
1Step 1: Identify the formulas of the fluorides
The formulas for the stable fluorides are as follows: \n\n- Lithium Fluoride (\(LiF\))\n- Beryllium Fluoride (\(BeF_2\))\n- Boron Trifluoride (\(BF_3\))\n- Carbon Tetrafluoride (\(CF_4\))\n- Nitrogen Trifluoride (\(NF_3\))\n- Oxygen Difluoride (\(OF_2\))\n\nThese fluorides are formed through different ionic and covalent bonds.
2Step 2: Describe the bonding characteristics
As we move from left to right across the period, the bonding in the element's stable fluoride changes. Lithium (Li) and Beryllium (Be) are metals and they form ionic bonds with Fluorine, thus Lithium Fluoride (\(LiF\)) and Beryllium Fluoride (\(BeF_2\)) are ionic compounds.\n\nFrom Boron (B) onwards, the elements are non-metals and they form covalent bonds. Thus, the compounds Boron Trifluoride (\(BF_3\)), Carbon Tetrafluoride (\(CF_4\)), Nitrogen Trifluoride (\(NF_3\)), and Oxygen Difluoride (\(OF_2\)) are covalently bonded. Furthermore, as you move from left to right, the number of fluorine atoms in the compounds tends to increase at first, then decrease, due to the variation in valence electrons of these elements. This is consistent with trends in the periodic table, specifically regarding atomic size, electronegativity, and ionization energy.
Key Concepts
ionic bondingcovalent bondingperiodic table trendsfluoride formation
ionic bonding
Ionic bonding occurs when atoms transfer electrons to achieve a complete outer shell, commonly resulting in the formation of a bond between a metal and a non-metal. In the case of lithium fluoride (
LiF
) and beryllium fluoride (
BeF_2
), this type of bonding is predominant. Here, the metallic elements, lithium and beryllium, donate their outermost electrons to fluorine atoms.
The fluorine atoms, being non-metals, accept these electrons to achieve stability, leading to the formation of ionic compounds. These compounds are characterized by strong attractions between the oppositely charged ions, resulting in a solid crystalline structure. This type of bonding typically results in materials with high melting and boiling points, as observed in lithium fluoride.
The fluorine atoms, being non-metals, accept these electrons to achieve stability, leading to the formation of ionic compounds. These compounds are characterized by strong attractions between the oppositely charged ions, resulting in a solid crystalline structure. This type of bonding typically results in materials with high melting and boiling points, as observed in lithium fluoride.
covalent bonding
Covalent bonding involves the sharing of electrons between non-metal atoms to fill their valence shells. As we move across the period from boron to oxygen, this bonding mechanism becomes more prevalent. For example, in boron trifluoride (
BF_3
), carbon tetrafluoride (
CF_4
), nitrogen trifluoride (
NF_3
), and oxygen difluoride (
OF_2
), each of these elements shares electrons with fluorine atoms.
This electron sharing forms stable molecules rather than ionic lattices. Consistency in valency showcases how non-metals exhibit strong covalent bonding to achieve noble gas configurations.
This electron sharing forms stable molecules rather than ionic lattices. Consistency in valency showcases how non-metals exhibit strong covalent bonding to achieve noble gas configurations.
- Boron, with three valence electrons, forms three covalent bonds with fluorine.
- Carbon, having four valence electrons, can form four covalent bonds, resulting in carbon tetrafluoride.
- Nitrogen with five valence electrons forms three covalent bonds due to its maximal combinatory efficiency with three fluorines.
- Oxygen, wanting two additional electrons, forms two covalent bonds in oxygen difluoride.
periodic table trends
Periodic table trends are pivotal in understanding the nature and behavior of elements as you move across a period from left to right. Some key trends include changes in atomic size, electronegativity, and ionization energy.
As you move from lithium (Li) to oxygen (O), several changes occur:
As you move from lithium (Li) to oxygen (O), several changes occur:
- Atomic Size: The atomic radius decreases because the increased number of protons in the nucleus pulls the electron cloud closer, even though the electron number also increases.
- Electronegativity: The ability of an atom to attract electrons in a chemical bond increases as you move across the period. Fluorine, being on the furthest right, is the most electronegative element.
- Ionization Energy: It becomes increasingly difficult to remove an electron from an atom due to the stronger attraction between the nucleus and the outer electrons, hence higher ionization energies are observed.
fluoride formation
Fluoride formation involves the interaction of various elements with fluorine to produce stable compounds. Fluorine is highly reactive due to its high electronegativity, striving to achieve a complete outer shell by gaining one electron.
When you examine the compounds formed with Li, Be, B, C, N, and O, a distinct pattern in fluoride formation emerges:
When you examine the compounds formed with Li, Be, B, C, N, and O, a distinct pattern in fluoride formation emerges:
- Lithium fluorides are created through the donation and acceptance of electrons, forming simple ionic bonds.
- Beryllium forms complex ionic bonds but also involves some covalent characteristics due to its smaller size and higher charge density.
- Boron and other elements switch to covalent bonding, as they share electrons with fluorine instead of transferring them.
Other exercises in this chapter
Problem 2
Fluorine is able to stabilize elements in very high oxidation states. For each of the elements \(\mathrm{Na}, \mathrm{Mg}, \mathrm{Al}, \mathrm{Si}\) P, S, and
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