Problem 1
Question
For which values of the real constants \(a, b, c, d\) is the function \(u(x, y)=a x^{3}+b x^{2} y+c x y^{2}+d y^{3}\) harmonic? Determine a harmonic conjugate of \(u\) in the cases where it is harmonic.
Step-by-Step Solution
Verified Answer
The function is harmonic for \(a = -\frac{c}{3}\), \(b = -3d\). Harmonic conjugate: \(v(x, y) = -bx^2y - cxy^2 - dy^3\) for these constants.
1Step 1: Understanding Harmonic Functions
A function is harmonic if it satisfies Laplace's equation: \(\frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0\). This means taking the second partial derivatives of the function and setting their sum to zero.
2Step 2: Calculate Second Partial Derivatives with Respect to x
First, find the first partial derivative of \(u(x, y)\) with respect to \(x\): \(u_x = 3ax^2 + 2bxy + cy^2\). Now, find the second partial derivative with respect to \(x\): \(u_{xx} = 6ax + 2by\).
3Step 3: Calculate Second Partial Derivatives with Respect to y
First, find the first partial derivative of \(u(x, y)\) with respect to \(y\): \(u_y = bx^2 + 2cxy + 3dy^2\). Now, find the second partial derivative with respect to \(y\): \(u_{yy} = 2cx + 6dy\).
4Step 4: Set Up Laplace's Equation
According to Laplace's equation: \(u_{xx} + u_{yy} = (6ax + 2by) + (2cx + 6dy) = 0\). Simplify to get \((6a + 2c)x + (2b + 6d)y = 0\).
5Step 5: Solve for Coefficients of x and y
For the equation \((6a + 2c)x + (2b + 6d)y = 0\) to be true for all \(x, y\), the coefficients must separately equal zero: \(6a + 2c = 0\) and \(2b + 6d = 0\).
6Step 6: Determine Values of Constants
From \(6a + 2c = 0\), we have \(a = -\frac{c}{3}\). From \(2b + 6d = 0\), we have \(b = -3d\). Any values of \(c\) and \(d\) will keep the function harmonic.
7Step 7: Find Harmonic Conjugate
Once we find the constants, calculate a harmonic conjugate \(v(x, y)\) such that \(v_x = -u_y\) and \(v_y = u_x\). Integrating, \(v(x, y) = -bx^2y - cxy^2 - dy^3\) when \(a = -\frac{c}{3}\) and \(b = -3d\).
Key Concepts
Laplace's EquationPartial DerivativesHarmonic Conjugate
Laplace's Equation
Laplace’s equation is a fundamental concept when studying harmonic functions. This equation states that for a function to be considered harmonic, it must satisfy the condition: \[ \frac{\partial^2 u}{\partial x^2} + \frac{\partial^2 u}{\partial y^2} = 0 \] This means that the sum of the second partial derivatives of the function with respect to each variable must be zero.
Laplace’s equation is a second-order partial differential equation, which is a cornerstone in fields like physics and engineering, especially in areas involving potential fields, such as electrostatics and fluid dynamics.
Laplace’s equation is a second-order partial differential equation, which is a cornerstone in fields like physics and engineering, especially in areas involving potential fields, such as electrostatics and fluid dynamics.
- Understanding whether a function is harmonic involves calculating its second partial derivatives.
- These derivatives help us understand how the function curves in the xy-plane.
- The condition of their sum being zero indicates a delicate balance in the function’s behavior.
Partial Derivatives
Partial derivatives are an essential mathematical tool used to understand the rates of change of multivariable functions. In simpler terms, they help us see how a function changes as one of the variables changes while keeping others constant.
For a function \( u(x, y) \), you take the partial derivative with respect to \( x \), holding \( y \) constant, and vice versa. Here’s how it looks:
For a function \( u(x, y) \), you take the partial derivative with respect to \( x \), holding \( y \) constant, and vice versa. Here’s how it looks:
- First partial derivative with respect to \( x \): \( u_x = \frac{\partial u}{\partial x} \).
- First partial derivative with respect to \( y \): \( u_y = \frac{\partial u}{\partial y} \).
- \( u_{xx} \): second derivative with respect to \( x \), shows how the slope \( u_x \) changes.
- \( u_{yy} \): second derivative with respect to \( y \), shows how the slope \( u_y \) changes.
Harmonic Conjugate
A harmonic conjugate is a function connected to a given harmonic function that makes the pair satisfy the Cauchy-Riemann equations. When a function \( u(x, y) \) is harmonic, you can often find a companion function \( v(x, y) \) such that together they form an analytic (complex differentiable) function. This means:
Finding the harmonic conjugate involves integrating these equations accordingly. Let one be \( u \), the other \( v \) such that they both satisfy **Laplace's equation** as well. Their combined ability to meet the Cauchy-Riemann conditions illuminates an underlying symmetry. Finding a harmonic conjugate essentially "completes" the harmonic nature, transitioning from a problem rooted purely in the real part to one embracing the symmetry of complex numbers.
- \( v_x = -u_y \)
- \( v_y = u_x \)
Finding the harmonic conjugate involves integrating these equations accordingly. Let one be \( u \), the other \( v \) such that they both satisfy **Laplace's equation** as well. Their combined ability to meet the Cauchy-Riemann conditions illuminates an underlying symmetry. Finding a harmonic conjugate essentially "completes" the harmonic nature, transitioning from a problem rooted purely in the real part to one embracing the symmetry of complex numbers.
Other exercises in this chapter
Problem 1
Let the function \(f\) be holomorphic in the open disk \(D\). Prove that each of the following conditions forces \(f\) to be constant: (a) \(f^{\prime}=0\) thro
View solution Problem 1
At which points are the following functions \(f\) differentiable? $$ \begin{array}{lll} \text { (a) } f(z)=x, & \text { (b) } f(z)=\bar{z}, & \text { (c) } f(z)
View solution Problem 2
Prove that Laplace's equation can be written in polar coordinates as $$ r^{2} \frac{\partial^{2} u}{\partial r^{2}}+r \frac{\partial u}{\partial r}+\frac{\parti
View solution