Problem 1
Question
For Problems \(1-32\), use Cramer's rule to find the solution set for each system. If the equations are dependent, simply indicate that there are infinitely many solutions. \(\left(\begin{array}{rl}2 x-y & =-2 \\ 3 x+2 y & =11\end{array}\right)\)
Step-by-Step Solution
Verified Answer
The solution is \((x, y) = (1, 4)\).
1Step 1: Identify the System of Equations
We start by identifying the system of equations given in the matrix form. The system is: 1. \(2x - y = -2\) 2. \(3x + 2y = 11\).
2Step 2: Define the Matrices and Determinants
For Cramer's Rule, the coefficient matrix is \(A = \begin{pmatrix} 2 & -1 \ 3 & 2 \end{pmatrix}\). The determinants needed are: 1. \(\Delta = \begin{vmatrix} 2 & -1 \ 3 & 2 \end{vmatrix}\) 2. \(\Delta_x = \begin{vmatrix} -2 & -1 \ 11 & 2 \end{vmatrix}\) 3. \(\Delta_y = \begin{vmatrix} 2 & -2 \ 3 & 11 \end{vmatrix}\).
3Step 3: Calculate the Determinant \(\Delta\)
The determinant \(\Delta\) is calculated as follows:\[\Delta = (2)(2) - (-1)(3) = 4 + 3 = 7\]
4Step 4: Calculate the Determinant \(\Delta_x\)
The determinant \(\Delta_x\) is calculated as:\[\Delta_x = (-2)(2) - (-1)(11) = -4 + 11 = 7\]
5Step 5: Calculate the Determinant \(\Delta_y\)
The determinant \(\Delta_y\) is calculated as:\[\Delta_y = (2)(11) - (-2)(3) = 22 + 6 = 28\]
6Step 6: Apply Cramer's Rule to Find \(x\) and \(y\)
Cramer's Rule states that:\[ x = \frac{\Delta_x}{\Delta} = \frac{7}{7} = 1\]\[ y = \frac{\Delta_y}{\Delta} = \frac{28}{7} = 4\].
7Step 7: Conclusion
The solution of the system of equations using Cramer's Rule is \((x, y) = (1, 4)\).
Key Concepts
System of EquationsDeterminantsMatrix AlgebraSolution Set
System of Equations
A system of equations is a collection of two or more equations with a common set of variables. Solving these equations involves finding the values of the variables that satisfy each equation simultaneously.
In our exercise, we are presented with the system of equations:
Understanding how to identify and set up the system correctly is crucial in determining the solution. The goal is always to find the unique solution, determine if there are infinitely many solutions, or conclude the system has no solution at all.
In our exercise, we are presented with the system of equations:
- \(2x - y = -2\)
- \(3x + 2y = 11\)
Understanding how to identify and set up the system correctly is crucial in determining the solution. The goal is always to find the unique solution, determine if there are infinitely many solutions, or conclude the system has no solution at all.
Determinants
Determinants are scalar values that are computed from the elements of a square matrix. They provide important properties of matrices and are essential when applying Cramer's Rule for solving systems of equations.
In our example, the determinant \(\Delta\) of the coefficient matrix \(A\) is calculated as shown in the steps provided:\[\Delta = \begin{vmatrix} 2 & -1 \ 3 & 2 \end{vmatrix} = (2)(2) - (-1)(3) = 4 + 3 = 7\] A non-zero determinant, such as \(7\), indicates that the matrix is invertible and that a unique solution exists for the system of equations.
Similarly, we find specific determinants \(\Delta_x\) and \(\Delta_y\) obtained by replacing one column in the coefficient matrix with the constants from the equations. These substituted determinants are key to finding the specific values for each variable using Cramer's Rule.
In our example, the determinant \(\Delta\) of the coefficient matrix \(A\) is calculated as shown in the steps provided:\[\Delta = \begin{vmatrix} 2 & -1 \ 3 & 2 \end{vmatrix} = (2)(2) - (-1)(3) = 4 + 3 = 7\] A non-zero determinant, such as \(7\), indicates that the matrix is invertible and that a unique solution exists for the system of equations.
Similarly, we find specific determinants \(\Delta_x\) and \(\Delta_y\) obtained by replacing one column in the coefficient matrix with the constants from the equations. These substituted determinants are key to finding the specific values for each variable using Cramer's Rule.
Matrix Algebra
Matrix algebra is an essential tool when working with systems of equations. It employs matrices to represent and manipulate data efficiently. In the context of our exercise, it is crucial for applying Cramer's Rule, which uses matrices to derive solutions.
Consider the coefficient matrix \(A\), comprised of the coefficients of the variables:\[A = \begin{pmatrix} 2 & -1 \ 3 & 2 \end{pmatrix}\] This matrix represents the system of equations in a compact form. Manipulating matrices and using operations like determinants allows for more streamlined calculations and solutions to complex systems.
Utilizing matrix algebra not only helps to solve systems but also aids in understanding deeper linear transformations and the behavior of linear models.
Consider the coefficient matrix \(A\), comprised of the coefficients of the variables:\[A = \begin{pmatrix} 2 & -1 \ 3 & 2 \end{pmatrix}\] This matrix represents the system of equations in a compact form. Manipulating matrices and using operations like determinants allows for more streamlined calculations and solutions to complex systems.
Utilizing matrix algebra not only helps to solve systems but also aids in understanding deeper linear transformations and the behavior of linear models.
Solution Set
The solution set of a system of equations is a collection of all ordered pairs that satisfy the whole system. In simple terms, solving a system of equations involves finding precise values for each variable.
In our example, this involves finding the values of \(x\) and \(y\). By applying Cramer's Rule using the determinants \(\Delta\), \(\Delta_x\), and \(\Delta_y\), we arrive at our unique solution:
In Cramer's Rule, the presence of a unique solution such as this suggests that the lines represented by each equation intersect at exactly one point in the plane, highlighting the intersections of solutions in two-dimensional space. If the determinant \(\Delta\) were zero, we would need to reconsider, as that scenario indicates either a dependent system with infinite solutions or no solution altogether.
In our example, this involves finding the values of \(x\) and \(y\). By applying Cramer's Rule using the determinants \(\Delta\), \(\Delta_x\), and \(\Delta_y\), we arrive at our unique solution:
- \(x = \frac{\Delta_x}{\Delta} = \frac{7}{7} = 1\)
- \(y = \frac{\Delta_y}{\Delta} = \frac{28}{7} = 4\)
In Cramer's Rule, the presence of a unique solution such as this suggests that the lines represented by each equation intersect at exactly one point in the plane, highlighting the intersections of solutions in two-dimensional space. If the determinant \(\Delta\) were zero, we would need to reconsider, as that scenario indicates either a dependent system with infinite solutions or no solution altogether.
Other exercises in this chapter
Problem 1
For Problems 1-22, find the partial fraction decomposition for each rational expression. See answers below. \(\frac{11 x-10}{(x-2)(x+1)}\)
View solution Problem 1
For Problems \(1-12\), evaluate each \(2 \times 2\) determinant by using Definition 11.1. \(\left|\begin{array}{ll}4 & 3 \\ 2 & 7\end{array}\right|\)
View solution Problem 1
For Problems \(1-10\), indicate whether each matrix is in reduced echelon form. \(\left[\begin{array}{ll:r}1 & 0 & -4 \\ 0 & 1 & 14\end{array}\right]\)
View solution Problem 2
Find the partial fraction decomposition for each rational expression. See answers below. \(\frac{11 x-2}{(x+3)(x-4)}\)
View solution