Problem 1
Question
Find the inverse of the matrix or state that the matrix is not invertible. $$ A=\left[\begin{array}{ll} 1 & 2 \\ 3 & 4 \end{array}\right] $$
Step-by-Step Solution
Verified Answer
The inverse of matrix \( A \) is \( \begin{bmatrix} -2 & 1 \\ 1.5 & -0.5 \end{bmatrix} \).
1Step 1: Review the Invertibility Condition
A 2x2 matrix is invertible if and only if its determinant is not zero. We first need to calculate the determinant of matrix \( A \).
2Step 2: Calculate the Determinant
The determinant of matrix \( A = \begin{bmatrix} 1 & 2 \ 3 & 4 \end{bmatrix} \) is calculated as: \[ ext{det}(A) = (1)(4) - (2)(3) = 4 - 6 = -2 \]Since the determinant is \(-2\), which is not zero, matrix \( A \) is invertible.
3Step 3: Apply the Inverse Formula for a 2x2 Matrix
The formula for the inverse of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is: \[ A^{-1} = \frac{1}{ad - bc} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \]
4Step 4: Substitute into the Formula
Using the matrix \( A = \begin{bmatrix} 1 & 2 \ 3 & 4 \end{bmatrix} \), substitute its values into the inverse formula:\[ A^{-1} = \frac{1}{-2} \begin{bmatrix} 4 & -2 \ -3 & 1 \end{bmatrix} = \begin{bmatrix} -2 & 1 \ 1.5 & -0.5 \end{bmatrix} \]
Key Concepts
Matrix DeterminantInvertibility Condition2x2 Matrix InverseMatrix Algebra
Matrix Determinant
One of the key steps in finding the inverse of a matrix is calculating its determinant. The determinant is a special number that can be derived from a square matrix. It helps in understanding certain properties of the matrix, such as whether it is invertible or not.
The determinant of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is calculated using the formula:
This value is crucial as it confirms the potential to find an inverse.
The determinant of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is calculated using the formula:
- (ad - bc): Multiply \( a \) by \( d \) and \( b \) by \( c \), then subtract the second result from the first.
This value is crucial as it confirms the potential to find an inverse.
Invertibility Condition
A matrix is considered invertible, or non-singular, if it meets specific conditions. The primary condition for a 2x2 matrix is that its determinant must not be zero. This is because the determinant being zero would imply that the matrix does not have a unique solution or cannot be inverted.
- The role of the determinant: If det(A) = 0, the matrix is singular and has no inverse. If det(A) ≠ 0, the matrix is non-singular and, thus, invertible.
2x2 Matrix Inverse
The inverse of a matrix is a matrix that, when multiplied by the original matrix, results in an identity matrix. For a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \), the inverse is found using a specific formula, provided that the determinant is non-zero.
- Inverse Formula: \[ A^{-1} = \frac{1}{ad - bc} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \]
- \( A^{-1} = \frac{1}{-2} \begin{bmatrix} 4 & -2 \ -3 & 1 \end{bmatrix} = \begin{bmatrix} -2 & 1 \ 1.5 & -0.5 \end{bmatrix} \)
Matrix Algebra
Matrix algebra is a branch of mathematics that deals with the study of matrices and the rules for their manipulation. Understanding matrix operations is essential for studying linear transformations, solving systems of linear equations, and many more applications.
- Basic Operations: Includes addition, subtraction, and multiplication of matrices.
- Identity Matrix: A special type of matrix that acts like the number 1 in matrix multiplication. An identity matrix for a 2x2 is \( \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix} \).
Other exercises in this chapter
Problem 1
In Exercises \(1-6\), find only the form needed to begin the process of partial fraction decomposition. Do not create the system of linear equations or attempt
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Compute the determinant of the given matrix. (Some of these matrices appeared in Exercises \(1-8\) in Section 8.4.) \(B=\left[\begin{array}{rr}12 & -7 \\ -5 & 3
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For each pair of matrices \(A\) and \(B\) in Exercises \(1-7,\) find the following, if defined \- \(3 A\) \- \(-B\) \- \(A^{2}\) \- \(A-2 B\) \- \(A B\) \- \(B
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State whether the given matrix is in reduced row echelon form, row echelon form only or in neither of those forms. $$ \left[\begin{array}{ll|l} 1 & 0 & 3 \\ 0 &
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