Problem 1
Question
Find the following sums and differences, and reduce to lowest terms. (Add or subtract as indicated.) $$\frac{3}{6}+\frac{1}{6}$$
Step-by-Step Solution
Verified Answer
The sum is \(\frac{2}{3}\).
1Step 1: Identify the Common Denominator
The given fractions are \(\frac{3}{6}\) and \(\frac{1}{6}\). Both fractions have the same denominator, which is 6. Therefore, we can directly add the numerators.
2Step 2: Add the Numerators
Since the denominator is the same, add the numerators: \(3 + 1 = 4\). So, the sum is \(\frac{4}{6}\).
3Step 3: Simplify the Fraction
To reduce \(\frac{4}{6}\) to its lowest terms, divide both the numerator and the denominator by their greatest common divisor (GCD), which is 2. \(\frac{4}{6} = \frac{4\div2}{6\div2} = \frac{2}{3}\).
Key Concepts
Common DenominatorSimplifying FractionsGreatest Common Divisor
Common Denominator
When adding or subtracting fractions, the fractions need a common denominator. This is because fractions represent parts of a whole, and to accurately add them together, they must be out of the same total (denominator).
A common denominator is simply a shared denominator between fractions. It's essentially the number that both fractions’ denominators can divide into without a remainder.
For instance, in the exercise \[\frac{3}{6} + \frac{1}{6}\], both fractions already share the denominator 6. This makes it easy to proceed directly to adding their numerators.
A common denominator is simply a shared denominator between fractions. It's essentially the number that both fractions’ denominators can divide into without a remainder.
For instance, in the exercise \[\frac{3}{6} + \frac{1}{6}\], both fractions already share the denominator 6. This makes it easy to proceed directly to adding their numerators.
- Identify or determine the shared denominator.
- Adjust only the numerators when denominators are the same.
- If the denominators aren't the same, find a least common multiple (LCM) of the denominators to use as the new denominator.
Simplifying Fractions
Simplifying fractions is the process of reducing them to their lowest terms. This means expressing the fraction in such a way that the numerator and the denominator have no common divisors other than 1. This simplified form is always preferred for its clarity and elegance.
To simplify a fraction, divide both the numerator and the denominator by their greatest common divisor (GCD). The GCD is the largest number that evenly divides both the numerator and the denominator.Consider the fraction from our example \(\frac{4}{6}\):
To simplify a fraction, divide both the numerator and the denominator by their greatest common divisor (GCD). The GCD is the largest number that evenly divides both the numerator and the denominator.Consider the fraction from our example \(\frac{4}{6}\):
- The GCD of 4 and 6 is 2.
- Divide both numerator and denominator by 2: \[\frac{4 \div 2}{6 \div 2} = \frac{2}{3}\]
Greatest Common Divisor
To simplify a fraction, finding the greatest common divisor (GCD) is essential. The GCD of two numbers is the greatest number that can divide both without leaving a remainder. It is a vital part of simplifying fractions.
Finding the GCD can be accomplished in various ways:
Finding the GCD can be accomplished in various ways:
- **Prime Factorization:** Break down both numbers into their prime factors and multiply the shared factors. For example, 4 factors into 2 x 2 and 6 factors into 2 x 3. The shared factor is 2.
- **Euclidean Algorithm:** A more advanced, step-by-step subtraction-based approach for larger numbers.
Other exercises in this chapter
Problem 1
Change each mixed number to an improper fraction. $$4 \frac{2}{3}$$
View solution Problem 1
Find each of the following products. (Multiply.) $$\frac{2}{3} \cdot \frac{4}{5}$$
View solution Problem 1
Find the quotient in each case by replacing the divisor by its reciprocal and multiplying. $$\frac{3}{4} \div \frac{1}{5}$$
View solution Problem 1
Identify each of the numbers below as either a prime number or a composite number. For those that are composite, give at least one divisor (factor) other than t
View solution