Problem 1
Question
Find the exact solutions by using the Quadratic Formula. \(8 x^{2}+18 x-5=0\)
Step-by-Step Solution
Verified Answer
The solutions are \(x = \frac{1}{4}\) and \(x = -\frac{5}{2}\).
1Step 1: Identify Coefficients
The quadratic equation is given in the standard form \(ax^2 + bx + c = 0\). Identify the coefficients: \(a = 8\), \(b = 18\), \(c = -5\).
2Step 2: Write Down the Quadratic Formula
The Quadratic Formula is \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). This formula will be used to find the roots of the given equation.
3Step 3: Calculate the Discriminant
The discriminant is \(b^2 - 4ac\). Substitute the values: \(b = 18\), \(a = 8\), and \(c = -5\) to get \(18^2 - 4 \times 8 \times (-5)\). Simplify to find \(324 + 160 = 484\).
4Step 4: Calculate the Square Root of the Discriminant
Find the square root of the discriminant \(\sqrt{484}\), which is \(22\).
5Step 5: Apply the Quadratic Formula
Substitute \(b = 18\), \(\sqrt{484} = 22\), and \(a = 8\) into the Quadratic Formula: \(x = \frac{-18 \pm 22}{2 \times 8}\).
6Step 6: Solve for the Two Possible Roots
Calculate the two possible roots using the \(\pm\) in the formula: \(x_1 = \frac{-18 + 22}{16}\) and \(x_2 = \frac{-18 - 22}{16}\). Simplify to find \(x_1 = \frac{4}{16} = \frac{1}{4}\) and \(x_2 = \frac{-40}{16} = -\frac{5}{2}\).
Key Concepts
DiscriminantRoots of quadratic equationsSolving quadratic equations
Discriminant
In quadratic equations, the discriminant plays a crucial role in determining the nature of the roots. It is found in the expression under the square root of the Quadratic Formula. For the equation \(ax^2 + bx + c = 0\), the discriminant is given by \(b^2 - 4ac\).
This value tells us:
This value tells us:
- If the discriminant is positive, the equation has two different real roots.
- If it is zero, there is exactly one real root (also called a repeated or double root).
- If it is negative, the roots are complex or imaginary, meaning there're no real solutions.
Roots of quadratic equations
Roots of quadratic equations are the solutions that satisfy the equation when substituted for \(x\). In a standard quadratic equation \(ax^2 + bx + c = 0\), roots can be found using different methods such as factoring, completing the square, or using the Quadratic Formula. Each method serves different purposes depending on the equation's coefficients and complexity.
With the Quadratic Formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), the roots are determined directly from the equation's coefficients without the need to factor or complete the square.
For instance, in our exercise, the roots were calculated by substituting in the coefficients to find \(\frac{1}{4}\) and \(-\frac{5}{2}\), which are the solutions for the equation \(8x^2 + 18x - 5 = 0\). This provides a reliable and straightforward approach to finding the roots regardless of how simple or complex the quadratic equation is.
With the Quadratic Formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), the roots are determined directly from the equation's coefficients without the need to factor or complete the square.
For instance, in our exercise, the roots were calculated by substituting in the coefficients to find \(\frac{1}{4}\) and \(-\frac{5}{2}\), which are the solutions for the equation \(8x^2 + 18x - 5 = 0\). This provides a reliable and straightforward approach to finding the roots regardless of how simple or complex the quadratic equation is.
Solving quadratic equations
Solving quadratic equations involves finding the values of \(x\) that satisfy the given equation. Several methods exist:
- Factoring: Involves expressing the equation as a product of linear factors and then setting each factor to zero. This method works best if the equation is easily factorable.
- Completing the Square: Involves rewriting the equation in the form \((x + p)^2 = q\) and then solving for \(x\). It's useful for deriving the vertex form of a parabola and when the quadratic doesn't factor neatly.
- Quadratic Formula: A universal method given by \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), which can solve any quadratic equation, regardless of factorability.
Other exercises in this chapter
Problem 1
Graph each function. $$ y=3(x+3)^{2} $$
View solution Problem 1
Solve each equation by using the Square Root Property. \(x^{2}+14 x+49=9\)
View solution Problem 1
Simplify. $$ \sqrt{56} $$
View solution Problem 1
Write a quadratic equation with the given root(s). Write the equation in standard form. \(-4,7\)
View solution