Problem 1
Question
Find \(f^{\prime}(x)\). $$f(x)=4 \cos x+2 \sin x$$
Step-by-Step Solution
Verified Answer
The derivative is \(f^{\prime}(x) = -4\sin x + 2\cos x\).
1Step 1: Identify Differentiation Rules
To find the derivative of the function \(f(x) = 4\cos x + 2\sin x\), you need to use the differentiation rules for trigonometric functions. Recall that the derivative of \(\cos x\) is \(-\sin x\) and the derivative of \(\sin x\) is \(\cos x\).
2Step 2: Differentiate Each Term Separately
Differentiate \(4\cos x\) and \(2\sin x\) separately. The derivative of \(4\cos x\) using the chain rule is \(4(-\sin x) = -4\sin x\). Similarly, the derivative of \(2\sin x\) is \(2(\cos x) = 2\cos x\).
3Step 3: Combine the Derivatives
Combine the derivatives of the separate terms to find \(f^{\prime}(x)\). Thus, \(f^{\prime}(x) = -4\sin x + 2\cos x\).
Key Concepts
Derivative of Trigonometric FunctionsDifferentiation RulesChain Rule
Derivative of Trigonometric Functions
Understanding the derivatives of trigonometric functions is crucial in calculus. Trigonometric functions, like \( \sin x \) and \( \cos x \), have specific rules for differentiation:
For instance, in the given function \( f(x) = 4\cos x + 2\sin x \), we're essentially applying these simple differentiation rules to each trigonometric term.
The importance of getting comfortable with these trigonometric derivatives is expanding your capability to navigate complex calculus problems with ease.
- The derivative of \( \sin x \) is \( \cos x \).
- The derivative of \( \cos x \) is \( -\sin x \).
For instance, in the given function \( f(x) = 4\cos x + 2\sin x \), we're essentially applying these simple differentiation rules to each trigonometric term.
The importance of getting comfortable with these trigonometric derivatives is expanding your capability to navigate complex calculus problems with ease.
Differentiation Rules
Differentiation rules make calculus problems manageable by offering clear strategies on how to approach the derivative of functions. When dealing with multiple terms, like \( f(x) = 4\cos x + 2\sin x \), it's essential to treat each term individually.
You'll often use the constant multiple rule which states that the derivative of \( c \cdot f(x) \) is \( c \cdot f^{\prime}(x) \), where \( c \) is a constant.
You'll often use the constant multiple rule which states that the derivative of \( c \cdot f(x) \) is \( c \cdot f^{\prime}(x) \), where \( c \) is a constant.
- The derivative of \( 4\cos x \) becomes \( 4(-\sin x) \) because of the constant multiple rule and the trigonometric derivative rule.
- Similarly, \( 2\sin x \) differentiates to \( 2\cos x \).
Chain Rule
In calculus, the chain rule is fundamental when dealing with composite functions, although it's not explicitly required in this example.
However, recognizing when to apply the chain rule is essential for other, more complex scenarios where a function is composed of another function. The chain rule is given by:\[\left( f(g(x)) \right)^{\prime} = f^\prime(g(x)) \cdot g^\prime(x)\]
In simpler terms, not only do you need to identify the inner and outer functions involved, but also differentiate each part correctly.
While our function here, \( 4\cos x + 2\sin x \), didn't require the use of the chain rule, familiarity with it is crucial as it frequently appears in differentiating nested expressions across calculus.
However, recognizing when to apply the chain rule is essential for other, more complex scenarios where a function is composed of another function. The chain rule is given by:\[\left( f(g(x)) \right)^{\prime} = f^\prime(g(x)) \cdot g^\prime(x)\]
In simpler terms, not only do you need to identify the inner and outer functions involved, but also differentiate each part correctly.
While our function here, \( 4\cos x + 2\sin x \), didn't require the use of the chain rule, familiarity with it is crucial as it frequently appears in differentiating nested expressions across calculus.
Other exercises in this chapter
Problem 1
Given that $$ f^{\prime}(0)=2, \quad g(0)=0 \quad \text { and } \quad g^{\prime}(0)=3 $$ find \((f \circ g)^{\prime}(0)\)
View solution Problem 1
Find \(d y / d x\) $$y=4 x^{7}$$
View solution Problem 1
Compute the derivative of the given function \(f(x)\) by (a) multiplying and then differentiating and (b) using the product rule. Verify that (a) and (b) yield
View solution Problem 2
Given that $$ f^{\prime}(9)=5, \quad g(2)=9 \quad \text { and } \quad g^{\prime}(2)=-3 $$ find \((f \circ g)^{\prime}(2)\)
View solution