Problem 1
Question
Find all solutions of the equation. $$\cos x+1=0$$
Step-by-Step Solution
Verified Answer
The solutions are \(x = \pi + 2k\pi\) for integer \(k\).
1Step 1: Isolate the Trigonometric Function
Begin by isolating the cosine function in the given equation: \[ \cos x + 1 = 0 \]Subtract 1 from both sides to solve for the cosine function:\[ \cos x = -1 \]
2Step 2: Determine Angle with Cosine of -1
Identify the angle(s) where the cosine value is -1. Cosine reaches -1 at specific angles on the unit circle. The primary angle is:\[ x = \pi + 2k\pi, \text{ for any integer } k \]This is because \(\cos(\pi) = -1\) and it repeats every full circle, \(2\pi\).
3Step 3: List General Solutions
The general solution for the equation \(\cos x = -1\) is:\[ x = \pi + 2k\pi, \text{ where } k \text{ is any integer} \]
Key Concepts
Cosine FunctionUnit CircleGeneral Solution
Cosine Function
The cosine function is one of the primary trigonometric functions, often abbreviated as "cos." It is a periodic function, which means that it repeats its values in a regular pattern over intervals. Cosine is specifically related to the x-coordinate of points on the unit circle. This function is an even function due to its symmetry about the vertical axis. With values ranging from
- -1 to 1
- cosine is particularly useful in calculating angles and lengths in right-angle triangles.
Unit Circle
The unit circle is a fundamental concept in trigonometry. It is a circle with a radius of 1, centered at the origin of a coordinate plane. The basic principle of the unit circle is that any point on it can be described using trigonometric functions. Here,
- the cosine of an angle corresponds to the x-coordinate of its point
- the sine of an angle corresponds to the y-coordinate.
General Solution
In trigonometry, finding the general solution to an equation means determining all possible solutions rather than just a single instance. For equations involving cosine, once you identify one angle where the requirement is met, you can find others using its periodic nature.
For the equation \[\cos x = -1\]in the exercise, we found that \[x = \pi\]is a solution. But due to the repeating nature of cosine values, any angle that is multiple of a full circle added to \(\pi\), forms another valid solution.
This can be expressed in general terms as \[x = \pi + 2k\pi\]where \(k\) is any integer. Hence, every increment of \(2\pi\) from \(\pi\) gives another angle where the cosine of x equals -1. This representation helps students understand that trigonometric equations can have infinitely many solutions, seamlessly fitting the periodic pattern of angles generated by trigonometric functions.
For the equation \[\cos x = -1\]in the exercise, we found that \[x = \pi\]is a solution. But due to the repeating nature of cosine values, any angle that is multiple of a full circle added to \(\pi\), forms another valid solution.
This can be expressed in general terms as \[x = \pi + 2k\pi\]where \(k\) is any integer. Hence, every increment of \(2\pi\) from \(\pi\) gives another angle where the cosine of x equals -1. This representation helps students understand that trigonometric equations can have infinitely many solutions, seamlessly fitting the periodic pattern of angles generated by trigonometric functions.
Other exercises in this chapter
Problem 1
Write the trigonometric expression in terms of sine and cosine, and then simplify. $$ \cos t \tan t $$
View solution Problem 1
Find the exact value of each expression, if it is defined. (a) \(\sin ^{-1} \frac{1}{2}\) (b) \(\cos ^{-1} \frac{1}{2}\) (c) \(\cos ^{-1} 2\)
View solution Problem 1
\(1-12\) : Use an addition or subtraction formula to find the exact value of the expression, as demonstrated in Example \(1 .\) $$ \sin 75^{\circ} $$
View solution Problem 1
1-8 Find \(\sin 2 x, \cos 2 x,\) and \(\tan 2 x\) from the given information. \(\sin x=\frac{5}{13}, \quad x\) in quadrant I
View solution