Problem 1
Question
Find a polynomial \(f(x)\) of degree 3 that has the indicated zeros and satisfies the given condition. $$-1,2,3 ; \quad f(-2)=80$$
Step-by-Step Solution
Verified Answer
The polynomial is \(f(x) = -4(x + 1)(x - 2)(x - 3)\).
1Step 1: Understand the Polynomial Structure
Since the polynomial is of degree 3 and given zeros are \(-1, 2, 3\), the polynomial can be expressed as \(f(x) = a(x + 1)(x - 2)(x - 3)\). We introduced the leading coefficient \(a\) since the polynomial could be any multiple of the basic form.
2Step 2: Substitute the Condition
Given \(f(-2) = 80\), substitute \(x = -2\) into the polynomial. This results in \(f(-2) = a(-2 + 1)(-2 - 2)(-2 - 3) = 80\). Simplify to get \(a(-1)(-4)(-5) = 80\).
3Step 3: Simplify and Solve for the Coefficient
Calculate the expression \(-1 \times -4 \times -5 = -20\), so the equation becomes \(-20a = 80\). Solve for \(a\) by dividing both sides by \(-20\), giving \(a = -4\).
4Step 4: Write the Polynomial with the Coefficient
Substitute \(a = -4\) back into the polynomial expression to get the final polynomial: \(f(x) = -4(x + 1)(x - 2)(x - 3)\).
Key Concepts
Degree of a PolynomialLeading CoefficientZeros of a PolynomialPolynomial Roots
Degree of a Polynomial
The degree of a polynomial is a fundamental concept that tells us about the largest exponent of the variable in a polynomial expression. In simpler terms, it is the highest power of the variable present in the expression when it is expanded. For instance, in the polynomial expression \(f(x) = x^3 + 2x^2 + x + 1\), the degree is 3 because the highest exponent of x is 3.
- The degree determines the number of solutions or roots the polynomial can have.
- It also suggests the behavior of the polynomial graph as x approaches positive or negative infinity.
Leading Coefficient
The leading coefficient of a polynomial is the coefficient of the term with the highest degree. In our exercise, after determining the possible structure of the polynomial from the given zeros, we defined the polynomial as \(f(x) = a(x + 1)(x - 2)(x - 3)\). Here, the variable 'a' represents the leading coefficient when the polynomial is fully expanded.
- The leading coefficient affects the steepness and direction of the graph of the polynomial.
- For example, a positive leading coefficient means the graph will eventually rise as it moves further away from the origin, while a negative one means it will fall.
Zeros of a Polynomial
Zeros of a polynomial, also known as roots, are the solutions to the equation \(f(x) = 0\). They are the x-values where the polynomial meets the x-axis. In our specific exercise, the zeros provided were -1, 2, and 3. These zeros can be found by setting each factor of the polynomial to zero:
- Zero at -1 from the factor \(x + 1\)
- Zero at 2 from the factor \(x - 2\)
- Zero at 3 from the factor \(x - 3\)
Polynomial Roots
Polynomial roots are synonymous with the zeros of the polynomial - they are the values of \(x\) which satisfy \(f(x) = 0\). Finding the roots of a polynomial is crucial as they help in graphing the function and understanding its behavior. In our exercise, we used the given roots of -1, 2, and 3 to establish the foundational structure of the polynomial function.
- Each root corresponds to a factor of the polynomial.
- The process of finding a polynomial from known roots involves reversing polynomial division.
Other exercises in this chapter
Problem 1
A polynomial \(f(x)\) with real coefficients and leading coefficient 1 has the given zero(s) and degree. Express \(f(x)\) as a product of linear and quadratic p
View solution Problem 1
(a) Sketch the graph of \(f\). (b) Find the domain \(D\) and range \(R\) of \(f .\) (c) Find the intervals on which \(f\) is increasing or is decreasing. $$f(x)
View solution Problem 1
Sketch the graph of \(f\) for the indicated value of \(c\) or \(a\) $$f(x)=2 x^{3}+c$$ (a) \(c=3\) (b) \(c=-3\)
View solution Problem 1
Find the quotient and remainder if \(f(x)\) is divided by \(p(x)\). $$f(x)=2 x^{4}-x^{3}-3 x^{2}+7 x-12 ; \quad p(x)=x^{2}-3$$
View solution