Problem 1
Question
Express the statement as a formula that involves the given variables and a constant of proportionality \(k\), and then determine the value of \(k\) from the given conditions. \(u\) is directly proportional to \(v\). If \(v=30\), then \(u=12\).
Step-by-Step Solution
Verified Answer
The formula is \(u = \frac{2}{5} v\) with \(k = \frac{2}{5}\).
1Step 1: Understand Direct Proportionality
When a quantity \(u\) is directly proportional to another quantity \(v\), it means that \(u\) can be expressed as \(u = k \cdot v\). Here, \(k\) is the constant of proportionality.
2Step 2: Write the Proportionality Formula
Based on the information given, express the relationship using the formula: \(u = k \cdot v\).
3Step 3: Substitute the Given Values
Substitute \(v = 30\) and \(u = 12\) into the formula: \[12 = k \cdot 30\]
4Step 4: Solve for \(k\)
Solve the equation \(12 = k \cdot 30\) for \(k\). Divide both sides by 30 to get \[k = \frac{12}{30} = \frac{2}{5}\].
Key Concepts
Constant of ProportionalityProportional RelationshipAlgebraic Expressions
Constant of Proportionality
The constant of proportionality is a key concept in understanding direct relationships between two quantities. It essentially tells us how much one variable changes when the other variable changes. In the context of direct proportionality, this constant is the fixed multiplier that connects the two variables. For our exercise, the relationship between variables is captured by the equation \( u = k \cdot v \), where \( k \) represents the constant of proportionality.
This constant remains unchanged as long as the relationship between the variables stays direct, meaning they change in a consistent manner. If \( u = 12 \) when \( v = 30 \), solving for \( k \) involves rearranging the equation to \( k = \frac{12}{30} \). Simplifying this gives \( k = \frac{2}{5} \). Thus, \( k \) quantifies how \( u \) scales with \( v \).
A few important things to remember about the constant of proportionality:
This constant remains unchanged as long as the relationship between the variables stays direct, meaning they change in a consistent manner. If \( u = 12 \) when \( v = 30 \), solving for \( k \) involves rearranging the equation to \( k = \frac{12}{30} \). Simplifying this gives \( k = \frac{2}{5} \). Thus, \( k \) quantifies how \( u \) scales with \( v \).
A few important things to remember about the constant of proportionality:
- It is specific to each proportional relationship.
- It must be consistent throughout the relationship.
- Changing either variable independently of this relationship changes the constant.
Proportional Relationship
A proportional relationship is a relationship between two variables where their ratio is constant. In these relationships, as one quantity increases, the other quantity increases at a consistent rate, and the same applies for decreases.
In our example, the proportional relationship is expressed as \( u = k \cdot v \). This equation shows that the ratio between \( u \) and \( v \) is \( k \), the constant of proportionality.
This type of relationship is linear, meaning a graph of this relationship will be a straight line passing through the origin, showcasing a steady, linear increase or decrease.
Some key aspects of proportional relationships include:
In our example, the proportional relationship is expressed as \( u = k \cdot v \). This equation shows that the ratio between \( u \) and \( v \) is \( k \), the constant of proportionality.
This type of relationship is linear, meaning a graph of this relationship will be a straight line passing through the origin, showcasing a steady, linear increase or decrease.
Some key aspects of proportional relationships include:
- The graph is a straight line.
- The line passes through the origin (0,0).
- The slope of the line represents the constant \( k \).
Algebraic Expressions
Algebraic expressions are a combination of numbers, variables, and operations that are used to represent mathematical ideas. They are fundamental in formulating equations that express relationships such as direct proportionality.
In the exercise, the algebraic expression \( u = k \cdot v \) is used to model the relationship between the variables \( u \) and \( v \). Here, \( u \) and \( v \) are variables, \( k \) is a constant, and the multiplication operation connects them.
When dealing with algebraic expressions in proportional relationships:
In the exercise, the algebraic expression \( u = k \cdot v \) is used to model the relationship between the variables \( u \) and \( v \). Here, \( u \) and \( v \) are variables, \( k \) is a constant, and the multiplication operation connects them.
When dealing with algebraic expressions in proportional relationships:
- Identify the variables involved.
- Determine the operations connecting them (here, multiplication).
- Recognize any constants that dictate the relationship dynamics.
Other exercises in this chapter
Problem 1
a) Sketch the graph of \(f .\) (b) Find the domain \(D\) and range \(R\) of \(f\). (c) Find the intervals on which \(f\) is increasing or is decreasing. $$ f(x)
View solution Problem 1
Exer. 1-10: A polynomial \(f(x)\) with real coefficients and leading coefficient 1 has the given zero(s) and degree. Express \(f(x)\) as a product of linear and
View solution Problem 2
Express the statement as a formula that involves the given variables and a constant of proportionality \(k\), and then determine the value of \(k\) from the giv
View solution