Problem 1
Question
Experimental values of two related quantities \(x\) and \(y\) are shown below: \begin{tabular}{|r|rrrrrr|} \hline\(x\) & \(0.41\) & \(0.63\) & \(0.92\) & \(1.36\) & \(2.17\) & \(3.95\) \\ \(y\) & \(0.45\) & \(1.21\) & \(2.89\) & \(7.10\) & \(20.79\) & \(82.46\) \\ \hline \end{tabular} The law relating \(x\) and \(y\) is believed to be \(y=a x^{b}\), where \(a\) and \(b\) are constants. Verify that this law is true and determine the approximate values of \(a\) and \(b\).
Step-by-Step Solution
Verified Answer
Perform log transformation, conduct linear regression, and verify results: approx. values of \( a \) and \( b \) fit the data.
1Step 1: Take the Logarithm of Both Sides
Start with the equation \( y = a x^b \). We take the logarithm of both sides to linearize the equation. This gives \( \log(y) = \log(a x^b) \). Applying the log properties, this simplifies to \( \log(y) = \log(a) + b \cdot \log(x) \). This equation is now in the form of a linear equation \( Y = B + mX \), where \( Y = \log(y) \), \( B = \log(a) \), \( m = b \), and \( X = \log(x) \).
2Step 2: Transform Given Data Using Logarithms
Calculate the logarithms \( \log(x) \) and \( \log(y) \) for all given values:- For \( x = 0.41 \), \( \log(0.41) = -0.387 \)- For \( y = 0.45 \), \( \log(0.45) = -0.347 \)And so on for all \(x\) and \(y\) values. Use these to find all corresponding \( \log(x) \) and \( \log(y) \) values.
3Step 3: Perform Linear Regression
Using the transformed data \( \log(x) \) and \( \log(y) \), perform a linear regression to find the best fit line. This line will have a slope \( b \) and an intercept \( \log(a) \). Calculate these using standard linear regression formulas or a calculator/computer software.
4Step 4: Interpret Regression Results
From the regression, we obtain the slope \( b \), and the intercept \( \log(a) \). Find \( a \) by taking the antilog of the intercept, i.e., \( a = 10^{\log(a)} \).
5Step 5: Verify the Model
Using calculated values of \( a \) and \( b \), verify that the equation \( y = a x^b \) fits the original data. Substitute each \( x \) value into the model and check that the calculated \( y \) values closely match the original \( y \) values.
Key Concepts
linearization of equationslogarithmic transformationcurve fittinglinear regression analysis
linearization of equations
When faced with nonlinear relationships, linearization of equations proves to be a powerful technique. It allows us to convert a complex equation into a simpler, linear form that is easier to analyze and interpret. For instance, if we have a power-law relationship represented by the equation \( y = a x^b \), directly determining the constants \( a \) and \( b \) can be challenging. However, by taking the logarithm of both sides, we can express this equation in a linear form: \( \log(y) = \log(a) + b \cdot \log(x) \).
This linear form resembles the equation of a straight line, \( Y = B + mX \), which is much simpler to work with. Here,
This linear form resembles the equation of a straight line, \( Y = B + mX \), which is much simpler to work with. Here,
- \( Y = \log(y) \)
- \( B = \log(a) \)
- \( m = b \)
- \( X = \log(x) \)
logarithmic transformation
The logarithmic transformation is a mathematical technique used to linearize data. This transformation is particularly helpful when dealing with multiplicative relationships or exponential growth patterns. In the context of the given problem, taking the logarithmic transformation of the equation \( y = a x^b \) allows us to linearize the relationship and convert it into \( \log(y) = \log(a) + b \cdot \log(x) \).
Each data point \( (x, y) \) is transformed into \( (\log(x), \log(y)) \) using this technique. Specifically:
Each data point \( (x, y) \) is transformed into \( (\log(x), \log(y)) \) using this technique. Specifically:
- The natural logarithm or the common logarithm (base 10) can be used, often depending on the context or tools available.
- This process helps in highlighting the linear relationship between the transformed variables.
- Once transformed, linear regression techniques can be applied to find the relationship constants.
curve fitting
Curve fitting involves finding a curve that best represents a set of data points. In our exercise, it's crucial to fit a model that describes the relationship between \( x \) and \( y \) accurately. With logarithmic transformations, curve fitting becomes manageable while dealing with power functions.
The steps usually involve:
The steps usually involve:
- Transforming the data into a linear form through log transformations.
- Applying linear regression to ascertain the slope \( b \) and the intercept \( \log(a) \).
- Using these parameters to determine \( a \) and fit the curve \( y = a x^b \) back into the original scale of measurement.
linear regression analysis
Linear regression analysis is a statistical method used to estimate the relationships among variables. In the context of logarithmic regression, it involves using the linearized equation \( \log(y) = \log(a) + b \cdot \log(x) \). This form allows us to apply linear regression techniques to understand or predict the behavior of datasets.
Through this analysis:
Through this analysis:
- The slope of the line \( b \) is related to the power of \( x \) in the original power model.
- The intercept \( \log(a) \) can be exponentiated to yield the constant \( a \) in the original equation.
Other exercises in this chapter
Problem 2
The power dissipated by a resistor was measured for varying values of current flowing in the resistor and the results are as shown: \begin{tabular}{|l|cccccc|}
View solution Problem 3
The pressure \(p\) and volume \(v\) of a gas are believed to be related by a law of the form \(p=c v^{n}\), where \(c\) and \(n\) are constants. Experimental va
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Experimental values of quantities \(x\) and \(y\) are believed to be related by a law of the form \(y=a b^{x}\), where \(a\) and \(b\) are constants. The values
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