Problem 1
Question
Expand \((1-2 x)^{5}\) by the binomial theorem.
Step-by-Step Solution
Verified Answer
The expansion of \((1 - 2x)^5\) is \(1 - 10x + 40x^2 - 80x^3 + 80x^4 - 32x^5\).
1Step 1: Understand the Formula
The binomial theorem states that \((a + b)^n\) can be expanded as \( \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k \). In this exercise, we use \(a = 1\), \(b = -2x\), and \(n = 5\).
2Step 2: Apply the Binomial Theorem
We will expand \((1 - 2x)^5\) by applying the binomial expansion formula. This involves calculating each term using: \( \binom{5}{k} (1)^{5-k} (-2x)^k \) for \(k = 0, 1, 2, 3, 4, 5\).
3Step 3: Calculate Each Term
Compute each term by substituting the values for \(k\):- For \(k = 0\): \( \binom{5}{0}(1)^{5-0}(-2x)^0 = 1 \)- For \(k = 1\): \( \binom{5}{1}(1)^{5-1}(-2x)^1 = -10x \)- For \(k = 2\): \( \binom{5}{2}(1)^{5-2}(-2x)^2 = 40x^2 \)- For \(k = 3\): \( \binom{5}{3}(1)^{5-3}(-2x)^3 = -80x^3 \)- For \(k = 4\): \( \binom{5}{4}(1)^{5-4}(-2x)^4 = 80x^4 \)- For \(k = 5\): \( \binom{5}{5}(1)^{5-5}(-2x)^5 = -32x^5 \)
4Step 4: Combine the Terms
Combine all the terms to construct the expanded expression:\((1 - 2x)^5 = 1 - 10x + 40x^2 - 80x^3 + 80x^4 - 32x^5\).
Key Concepts
Binomial ExpansionCombinatoricsExponentiationPolynomial Expansion
Binomial Expansion
The process of binomial expansion involves turning expressions of the form \((a + b)^n\) into a sum of terms, each involving powers of \(a\) and \(b\). This expansion is made possible with the binomial theorem, which provides a systematic way to break down and calculate each term in the expansion using the formula:
In practical applications, binomial expansion allows us to compute powers of polynomials without the need for lengthy multiplication.
- \((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\)
In practical applications, binomial expansion allows us to compute powers of polynomials without the need for lengthy multiplication.
Combinatorics
Combinatorics is an area of mathematics focusing on counting and arrangement. Within binomial expansion, combinatorics plays a vital role through the use of binomial coefficients, denoted as \(\binom{n}{k}\). Each binomial coefficient represents the number of ways \(k\) items can be chosen from \(n\) items, also known as "n choose k."
These coefficients can be calculated using the formula:
This conceptual understanding of combinatorics ensures accuracy when working with larger powers and more complex expansions.
These coefficients can be calculated using the formula:
- \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\)
This conceptual understanding of combinatorics ensures accuracy when working with larger powers and more complex expansions.
Exponentiation
Exponentiation is the mathematical operation involving numbers raised to powers. This core concept within the binomial expansion helps in breaking down each component of an expression into terms involving powers.
For a polynomial like \((1 - 2x)^5\), exponentiation is used at each step of the expansion to calculate powers of \(-2x\) for different values of \(k\). The term \((-2x)^k\) changes from one term to another as \(k\) increases, allowing us to identify the correct power to use in each part of the expanded polynomial.
For a polynomial like \((1 - 2x)^5\), exponentiation is used at each step of the expansion to calculate powers of \(-2x\) for different values of \(k\). The term \((-2x)^k\) changes from one term to another as \(k\) increases, allowing us to identify the correct power to use in each part of the expanded polynomial.
- For example, when \(k = 2\), the operation \((-2x)^2\) results in \(4x^2\).
- This ensures each term in the series is accurately represented with its corresponding power.
Polynomial Expansion
Polynomial expansion references the full breakdown of expressions like \((1 - 2x)^5\) into simpler components expressed as a sum of terms.
Each polynomial expansion involves transforming higher powers into sums of multiple terms that reveal individual parts by leveraging the binomial theorem.
The resulting expanded form of \((1 - 2x)^5\) is a polynomial of degree 5:
Each polynomial expansion involves transforming higher powers into sums of multiple terms that reveal individual parts by leveraging the binomial theorem.
The resulting expanded form of \((1 - 2x)^5\) is a polynomial of degree 5:
- \(1 - 10x + 40x^2 - 80x^3 + 80x^4 - 32x^5\)
- Understanding polynomial expansion is crucial for solving mathematical equations in various fields such as physics, engineering, and economics.
- It provides a straightforward method to approach mathematical problems involving higher degree expressions.
Other exercises in this chapter
Problem 1
Expand \(\left(x^{2}+2 y\right)^{5}\) by the binomial theorem.
View solution Problem 1
If the coefficient of 7 th and 13 th term in the expansion of \((1+x)^{n}\) are equal, then \(n=\) (a) 10 (b) 15 (c) 18 (d) 20
View solution Problem 2
Expand \(\left(\frac{2}{x}-\frac{x}{2}\right)^{5}\) by the binomial theorem.
View solution