Problem 1
Question
Exer. 1-8: Express in terms of logarithms of \(x, y, z,\) or \(w\) $$\text { (a) } \log _{4}(x z)$$ (b) \(\log _{4}(y / x)\) (c) \(\log _{4} \sqrt[3]{z}\)
Step-by-Step Solution
Verified Answer
(a) \(\log_4(x) + \log_4(z)\), (b) \(\log_4(y) - \log_4(x)\), (c) \(\frac{1}{3} \log_4(z)\).
1Step 1: Review Logarithm Product Rule
The logarithm product rule states that \( \log_b(mn) = \log_b(m) + \log_b(n) \). This rule will be useful for part (a) to separate the variables inside the logarithm.
2Step 2: Apply Product Rule to (a)
For (a), \( \log_{4}(xz) \), we can apply the product rule: \( \log_{4}(x) + \log_{4}(z) \). This expresses the logarithm in terms of \(x\) and \(z\).
3Step 3: Review Logarithm Quotient Rule
The logarithm quotient rule states that \( \log_b\left(\frac{m}{n}\right) = \log_b(m) - \log_b(n) \). This rule will help simplify part (b).
4Step 4: Apply Quotient Rule to (b)
For (b), \( \log_{4}(\frac{y}{x}) \), use the quotient rule: \( \log_{4}(y) - \log_{4}(x) \). This provides an expression in terms of \(y\) and \(x\).
5Step 5: Review Logarithm Power Rule
The logarithm power rule is \( \log_b(m^n) = n \cdot \log_b(m) \). We can use this rule for part (c) to handle the cube root.
6Step 6: Apply Power Rule to (c)
For (c), \( \log_{4}(\sqrt[3]{z}) \), recognize it as \(z^{1/3}\). Use the power rule to get \( \frac{1}{3} \cdot \log_{4}(z) \).
Key Concepts
Logarithm Product RuleLogarithm Quotient RuleLogarithm Power Rule
Logarithm Product Rule
When dealing with products inside a logarithm, the Product Rule for logarithms is your friend. This rule tells us that the logarithm of a product is simply the sum of the logarithms of the factors. For instance, if we have
- \( \log_b(mn) \),
- \( \log_b(m) + \log_b(n) \).
Logarithm Quotient Rule
Logarithms offer a straightforward way to handle division through the Quotient Rule. The essence of this rule is that the logarithm of a quotient is equal to the difference of the logarithms of the numerator and the denominator. In a mathematical form, this can be expressed as:
- \( \log_b\left(\frac{m}{n}\right) = \log_b(m) - \log_b(n) \).
Logarithm Power Rule
The Power Rule for logarithms sheds light on how to deal with exponents within a logarithmic expression. This useful property states that the logarithm of a power is the exponent times the logarithm of the base. It is mathematically defined as:
- \( \log_b(m^n) = n \cdot \log_b(m) \).
Other exercises in this chapter
Problem 1
Change to logarithmic form. (a) \(4^{3}=64\) (b) \(4^{-3}=\frac{1}{64}\) (c) \(t^{\prime}=s\) (d) \(3^{x}=4-t\) (e) \(5^{7 t}=\frac{a+b}{a}\) (f) \((0.7)^{y}=5.
View solution Problem 1
Solve the equation. $$7^{x+6}=7^{3 x-4}$$
View solution Problem 1
Find \(\begin{array}{ll}\text { (a) } f^{-1}(5) & \text { (b) } g^{-1}(6)\end{array}\) $$\begin{array}{|c|c|c|c|} \hline x & 2 & 4 & 6 \\ \hline f(x) & 3 & 5 &
View solution Problem 2
Change to logarithmic form. (a) \(3^{3}=243\) (b) \(3^{-4}=\frac{1}{81}\) (c) \(c^{r}=d\) (d) \(7^{x}=100 p\) (e) \(3^{-2 x}=\frac{P}{F}\) (f) \((0.9)^{y}=\frac
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