Problem 1
Question
Evaluate the limits. $$ \lim _{x \rightarrow \infty} \frac{2 x^{2}-3 x+5}{x^{4}-2 x+1} $$
Step-by-Step Solution
Verified Answer
The limit as \( x \to \infty \) is 0.
1Step 1: Identify Leading Terms
To evaluate the limit of a rational function as \( x \to \infty \), identify the leading terms in the numerator and the denominator. The leading term in the numerator is \( 2x^2 \), and the leading term in the denominator is \( x^4 \).
2Step 2: Simplify the Expression
Divide both the numerator and the denominator by \( x^4 \), the highest power of \( x \) present. This gives us: \[\frac{\frac{2x^2}{x^4} - \frac{3x}{x^4} + \frac{5}{x^4}}{\frac{x^4}{x^4} - \frac{2x}{x^4} + \frac{1}{x^4}}\]Simplifying each term, we get: \[\frac{\frac{2}{x^2} - \frac{3}{x^3} + \frac{5}{x^4}}{1 - \frac{2}{x^3} + \frac{1}{x^4}}\]
3Step 3: Evaluate Each Term As \( x \to \infty \)
As \( x \to \infty \), terms like \( \frac{1}{x^2} \), \( \frac{1}{x^3} \), and \( \frac{1}{x^4} \) all approach zero. Therefore, the expression simplifies as follows:\[\lim_{x \to \infty} \frac{0 - 0 + 0}{1 - 0 + 0} = 0\]
4Step 4: State the Result
Since all terms in the numerator approach zero, and the denominator approaches 1, the entire expression approaches zero as \( x \to \infty \). The limit is therefore zero.
Key Concepts
Leading Terms in Rational FunctionsSimplifying Expressions by Dividing by Highest PowersEvaluating Limits at Infinity
Leading Terms in Rational Functions
When evaluating limits at infinity for rational functions, identifying the leading terms is crucial. Leading terms are the terms with the highest exponents on the variable, often the most significant in determining the behavior of the function as the variable approaches infinity. In the example provided, the leading term in the numerator is \(2x^2\), while the leading term in the denominator is \(x^4\).
- The leading terms give us insight into how the degrees of the polynomials compare, which is vital for simplification and evaluating the limits.
- By focusing on these terms, we can ignore smaller terms that contribute less significantly to the function's growth or decay.
- This understanding allows us to determine how the fraction behaves when \(x\) becomes very large.
Simplifying Expressions by Dividing by Highest Powers
Once leading terms are identified, the next step is simplifying the rational function. Simplification involves dividing every term in both the numerator and denominator by the highest power of \(x\) present in the denominator, which in this case is \(x^4\). This simplification process changes our original problem to:
- \(\frac{\frac{2}{x^2} - \frac{3}{x^3} + \frac{5}{x^4}}{1 - \frac{2}{x^3} + \frac{1}{x^4}}\)
- Here, each term is now expressed with \(x\) in the denominator, and as \(x\) grows larger, these fractional expressions tend toward zero.
- This reveals the true nature of the limit of the function, as the dominant terms are diminished to 0.
Evaluating Limits at Infinity
After simplifying, the next step is to evaluate each term as \(x\) approaches infinity. For the terms \(\frac{2}{x^2}\), \(\frac{3}{x^3}\), and \(\frac{5}{x^4}\) in the numerator, and \(\frac{2}{x^3}\) and \(\frac{1}{x^4}\) in the denominator, we observe:
- As \(x\) grows, these terms approach zero because dividing a constant by an increasingly large number results in values approaching zero.
- This leaves us with the simplified limit \(\frac{0 - 0 + 0}{1 - 0 + 0}\), which simplifies to \(\frac{0}{1}\), clearly 0.
- This shows that the limit of the whole expression as \(x\) tends towards infinity is zero.
Other exercises in this chapter
Problem 1
Let \(f(x)=x^{2}-2, \quad 0 \leq x \leq 2\). (a) Graph \(y=f(x)\) for \(0 \leq x \leq 2\). (b) Show that \(f(0)
View solution Problem 1
In Problems \(1-4\), show that each function is continuous at the given value. $$ f(x)=2 x, c=1 $$
View solution Problem 2
Evaluate the trigonometric limits. $$ \lim _{x \rightarrow 0} \frac{\sin (2 x)}{4 x} $$
View solution Problem 2
Find the values of \(x\) such that $$ |3 x-9|
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