Problem 1
Question
Es sei \(R\) ein kommutativer Ring mit 1. Begründen Sie, dass die Menge \(R[[X]]:=\left\\{P \mid P: \mathbb{N}_{0} \rightarrow R\right\\}\) mit den Verknüpfungen \(+\) und \(\cdot\), die für \(P, Q \in R[[X]]\) wie folgt erklärt sind: $$ (P+Q)(m):=P(m)+Q(m),(P Q)(m):=\sum_{i+j=m} P(i) Q(j) $$ ein kommutativer Erweiterungsring mit 1 von \(R[X]\) ist - der Ring der formalen Potenzreihen oder kürzer Potenzreihenring über \(R\). Wir schreiben \(P=\sum_{i \in \mathbb{N}_{0}} a_{i} X^{i}\) oder \(\sum_{i=0}^{\infty} a_{i} X^{i}\) (also \(P(i)=a_{i}\) ) für \(P \in R[[X]]\) und nennen die Elemente aus \(R[[X]]\) Potenzreihen. Begründen Sie außerdem: (a) \(R[[X]]\) ist genau dann ein Integritätsbereich, wenn \(R\) ein Integritätsbereich ist. (b) Eine Potenzreihe \(P=\sum_{i \in \mathbb{N}_{0}} a_{i} X^{i} \in R[[X]]\) ist genau dann invertierbar, wenn \(a_{0} \in R^{\times}\)gilt, d.h. \(R[[X]]^{\times}=\left\\{\sum_{i=0}^{\infty} a_{i} X^{i} \mid a_{0} \in R^{\times}\right\\}\) (c) Bestimmen Sie in \(R[[X]]\) das Inverse von \(1-X\) und \(1-X^{2}\).
Step-by-Step Solution
VerifiedKey Concepts
Commutative Ring
- Commutativity: Both addition and multiplication follow the commutative law. This means for any elements \(a\) and \(b\) in the ring, \(a + b = b + a\) and \(ab = ba\).
- Associativity: Both operations are associative. Thus, \((a + b) + c = a + (b + c)\) and \((ab)c = a(bc)\).
- Distributivity: Multiplication distributes over addition. That is, \(a(b + c) = ab + ac\).
Integral Domain
- The coefficient ring \(R\) itself must be an integral domain.
- This implies that if \(R\) has no zero divisors, then \(R[[X]]\) will inherit this property.
- Conversely, if \(R\) does have zero divisors, \(R[[X]]\) cannot be an integral domain because these zero divisors would propagate through the series operations.
Invertibility
- The constant term \(a_0\) of the series must be invertible in \(R\).
- This ensures that the series can interact with another series \(Q(X)\) such that \(P(X)Q(X) = 1\) where 1 represents the series whose constant term is 1 and other coefficients are 0.
- If \(a_0\) is not invertible in \(R\), it is impossible to maintain the necessary product of series to achieve unity.
Ring Extension
- When discussing \(R[X]\) and \(R[[X]]\), the extension from polynomials to formal power series is evident.
- \(R[X]\), the ring of polynomials, consists of elements where only finitely many coefficients are non-zero.
- When extending to \(R[[X]]\), series can have infinitely many non-zero coefficients – moving from polynomials to series allows us to operate within a broader context while preserving ring structure.
- This extension allows deeper analysis and manipulation of series akin to polynomials but with increased flexibility and applications in analysis and number theory.