Problem 1
Question
$$e^{\frac{\pi}{6} i}=\cos \frac{\pi}{6}+i \sin \frac{\pi}{6}=\frac{\sqrt{3}}{2}+\frac{1}{2} i$$
Step-by-Step Solution
Verified Answer
Yes, the expression is verified correctly using Euler's formula.
1Step 1: Understand the Problem
We want to verify the equality given: \( e^{\frac{\pi}{6} i} = \cos \frac{\pi}{6} + i \sin \frac{\pi}{6} \), and show it equals \( \frac{\sqrt{3}}{2} + \frac{1}{2} i \). This involves using Euler's formula: \( e^{ix} = \cos x + i \sin x \).
2Step 2: Apply Euler's Formula
Recall Euler's formula: \( e^{ix} = \cos x + i \sin x \). For \( x = \frac{\pi}{6} \), this becomes \( e^{\frac{\pi}{6} i} = \cos \frac{\pi}{6} + i \sin \frac{\pi}{6} \). Substitute \( x = \frac{\pi}{6} \) into this formula.
3Step 3: Calculate \( \cos \frac{\pi}{6} \) and \( \sin \frac{\pi}{6} \)
From trigonometric values: \( \cos \frac{\pi}{6} \) is known to be \( \frac{\sqrt{3}}{2} \) and \( \sin \frac{\pi}{6} \) is \( \frac{1}{2} \). Therefore, \( \cos \frac{\pi}{6} + i \sin \frac{\pi}{6} = \frac{\sqrt{3}}{2} + \frac{1}{2} i \).
4Step 4: Verify the Equality
The expression \( \cos \frac{\pi}{6} + i \sin \frac{\pi}{6} = \frac{\sqrt{3}}{2} + \frac{1}{2} i \) matches exactly with the given expression in the problem. This confirms that \( e^{\frac{\pi}{6} i} = \frac{\sqrt{3}}{2} + \frac{1}{2} i \) as expected.
Key Concepts
Complex NumbersTrigonometric FunctionsExponential Functions
Complex Numbers
Complex numbers are a major cornerstone of advanced mathematics, expanding our understanding of numbers beyond the real number line. Essentially, a complex number is a number that has two components: a real part and an imaginary part. It is expressed in the form \( a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) is the imaginary unit. The imaginary unit \( i \) has a unique property where \( i^2 = -1 \). Here's why complex numbers are important:
- They allow us to solve equations that have no real solutions, like \( x^2 + 1 = 0 \).
- They provide a complete field for algebraic operations.
- They're crucial in various fields such as engineering, physics, and computer science.
Trigonometric Functions
Trigonometric functions, primarily sine and cosine, are fundamental concepts not only in geometry but also in many areas of mathematics, including calculus and complex analysis. They are particularly crucial when we deal with periodic phenomena, such as waves and oscillations. In trigonometry, the sine and cosine of an angle correspond to the y-coordinate and x-coordinate of a point on the unit circle. For the angle \( \frac{\pi}{6} \), these trigonometric values are:
- \( \cos \frac{\pi}{6} = \frac{\sqrt{3}}{2} \)
- \( \sin \frac{\pi}{6} = \frac{1}{2} \)
Exponential Functions
Exponential functions are pivotal in mathematics, often serving as models for growth, decay, and complex oscillations. The most notable exponential function is the natural exponential function \( e^x \), where \( e \) is approximately 2.718, known as Euler's number. Exponential functions have interesting properties, such as the ability for any exponential function of the form \( e^{ix} \) to be expressed in terms of trigonometric functions via Euler’s formula:\[ e^{ix} = \cos x + i\sin x \]This mathematics reveals a fascinating link between exponential and trigonometric functions. The formula shows that while exponential functions grow or decay in real numbers, when extended to imaginary numbers, they describe rotations and oscillations.This characteristic is vital in fields like signal processing and quantum mechanics, where oscillatory behaviors are pivotal. Understanding how exponential functions can transform into trigonometric expressions through Euler's formula is essential for grasping the deeper ties between different mathematical disciplines.
Other exercises in this chapter
Problem 1
$$\cos (3 i)=\cosh 3=10.0677$$
View solution Problem 1
Substituting \(y=2\) into \(u=x^{2}-y^{2}, v=2 x y\) gives the parametric equations \(u=x^{2}-4, v=4 x.\) Using \(x=v / 4\) the first equation gives \(u=v^{2} /
View solution Problem 1
$$2(\cos 2 \pi+i \sin 2 \pi)$$
View solution Problem 2
$$\sin (-2 i)=i \sinh (-2)=-3.6269 i$$
View solution