Problem 1
Question
Determine whether or not the function is a power function. If it is a power function, write it in the form \(y=k x^{p}\) and give the values of \(k\) and \(p\) $$y=\frac{x}{5}$$
Step-by-Step Solution
Verified Answer
Yes, it is a power function with \(k=\frac{1}{5}\) and \(p=1\).
1Step 1: Identify the given function
The given function is \( y = \frac{x}{5} \). We need to determine if this can be expressed as a power function of the form \( y = kx^p \).
2Step 2: Simplify the function to check for power function form
Rewrite the given function \( y = \frac{x}{5} \) in a way that fits the form \( y = kx^p \). Specifically, we can write it as \( y = \frac{1}{5}x^1 \), which resembles the form of a power function where \( k = \frac{1}{5} \) and \( p = 1 \).
3Step 3: Verify the power function
Verify that the rewritten function \( y = \frac{1}{5}x^1 \) indeed represents a power function. In this case, \( k \) is a constant \( \frac{1}{5} \) and \( p \) is the exponent \( 1 \), confirming it is a power function.
Key Concepts
Power Function FormConstant CoefficientExponent
Power Function Form
A power function has the form \( y = kx^p \), making it a crucial component in understanding different types of mathematical equations and their behavior. When we say something is a power function, we're referring to any function where a single term is raised to a constant exponent.
- Form Elements: It must have one term in the form of a variable raised to the power of an exponent.
- Variable: Typically, the variable involved is \( x \), but it could be any other variable.
- Simplicity: Unlike other polynomials that may have a sum of multiple terms, a power function only focuses on one term with an exponent.
Constant Coefficient
In the context of power functions, the constant coefficient \( k \) plays a vital role in scaling the effect of the function. It is the numerical part that stays constant regardless of the value of the variable \( x \).
- Value of \( k \): It's the number that multiplies the variable raised to a power. For example, in \( y = \frac{1}{5}x^1 \), \( k = \frac{1}{5} \).
- Influence: The coefficient determines the function's vertical stretch or shrink. It impacts the steepness of the graph, affecting how quickly the output increases or decreases.
Exponent
The exponent \( p \) in a power function determines the degree and direction of the function. This impacts the curvature and overall shape of the graph.
- Role of \( p \): In \( y = kx^p \), \( p \) signifies the power to which the variable is raised. In \( y = \frac{1}{5}x^1 \), \( p = 1 \).
- Impact on Graph: A positive exponent leads to a standard power function shape, whereas a negative \( p \) would flip the curve, introducing new patterns like reciprocal functions.
- Nature of p:**: Higher exponents mean curves will rise or drop faster as \( x \) moves away from zero. Linear: For \( p=1 \), the function is linear. The graph is a straight line.
Other exercises in this chapter
Problem 1
Graph the function. What is the amplitude and period? $$y=3 \sin x$$
View solution Problem 1
In Problems \(1-3,\) find the following: (a) \(\quad f(g(x))\) (b) \(g(f(x))\) (c) \(f(f(x))\) $$f(x)=5 x-1 \text { and } g(x)=3 x+2$$
View solution Problem 1
For Problems \(1-16,\) solve for \(t\) using natural logarithms. $$10=2^{t}$$
View solution Problem 1
The following functions give the populations of four towns with time \(t\) in years. (i) \(\quad P=600(1.12)^{t}\) (ii) \(\quad P=1,000(1.03)^{t}\) (iii) \(\qua
View solution