Problem 1
Question
Determine whether each function is a one-to-one function. If it is one-to-one, list the inverse function by switching coordinates, or inputs and outputs. \(g=\\{(0,3),(3,7),(6,7),(-2,-2)\\}\)
Step-by-Step Solution
Verified Answer
The function is not one-to-one, so it does not have an inverse.
1Step 1: Understanding the Problem
We are given a function represented as a set of ordered pairs: \(g=\{(0,3),(3,7),(6,7),(-2,-2)\}\). We need to determine whether this function is one-to-one. A one-to-one function has no repetition of the output values.
2Step 2: Check for Output Repetition
To determine if the function is one-to-one, check if any y-value is repeated in the set of ordered pairs. The function \(g\) has the ordered pairs: \( (0,3), (3,7), (6,7), (-2,-2)\). Notice that the y-value 7 is repeated twice, at points (3,7) and (6,7).
3Step 3: Conclusion: Not One-to-One
Since the y-value 7 is repeated for different x-values (3 and 6), the function \(g\) is not a one-to-one function. A one-to-one function cannot have duplicate outputs for different inputs.
4Step 4: Inverse Check
Since the function is not one-to-one, it cannot have an inverse function that is also a function. For an inverse to exist as a function, each output value of \(g\) must map to exactly one input value, which is not the case here.
Key Concepts
Inverse FunctionOrdered PairsOutput RepetitionY-Value Analysis
Inverse Function
An inverse function is essentially about reversing the roles of inputs and outputs in a given function. When you have a function, say \(f(x)\), its inverse \(f^{-1}(x)\) will take the output \(f(x)\) as input and return \(x\). This means:
Thus, no clear path from output back to input would be possible. This is why checking the one-to-one nature is vital before switching coordinates to form an inverse. In the presence of repetition like in our example with \(g={0,3},{3,7},{6,7},{-2,-2}\), where 7 appears twice, a proper function inverse cannot exist.
- If \(f(a) = b\), then \(f^{-1}(b) = a\).
Thus, no clear path from output back to input would be possible. This is why checking the one-to-one nature is vital before switching coordinates to form an inverse. In the presence of repetition like in our example with \(g={0,3},{3,7},{6,7},{-2,-2}\), where 7 appears twice, a proper function inverse cannot exist.
Ordered Pairs
Ordered pairs are a fascinating way to express relationships between two entities, often noted as \((x, y)\). Here \(x\) is called the input or domain, while \(y\) is the output or range. When functions are presented as ordered pairs, each pair indicates that a specific input yields a specific output.
- For instance, \((0,3)\) tells us that 0 maps to 3.
- In the case of our function \(g\), the pairs \((3,7)\) and \((6,7)\) indicate that both 3 and 6 map to the same output of 7.
Output Repetition
Output repetition within a function occurs when different inputs correspond to the same output value, leading to a potential problem when assessing the function's properties. For instance, in the function \(g\) from the exercise, notice the following output repetition:
- The outputs for the inputs 3 and 6 are both 7, showing a duplication.
Y-Value Analysis
Y-value analysis involves carefully examining the outputs (the \(y\)-values) of each ordered pair in a function to decide if the function is one-to-one. By scanning through the \(y\)-values:
- Identifying repetitions becomes straightforward.
- A function like \(g\) is not one-to-one as we see 7 twice as a \(y\)-value.
Other exercises in this chapter
Problem 1
Use a calculator to approximate each logarithm to four decimal places. $$ \log 8 $$
View solution Problem 1
For the functions \(f\) and \(g\), find a. \((f+g)(x)\), b. \((f-g)(x), c .(f \cdot g)(x)\), and d. \(\left(\frac{f}{g}\right)(x)\). $$ f(x)=x-7 ; g(x)=2 x+1 $$
View solution Problem 1
Graph each exponential function. $$ y=5^{x} $$
View solution Problem 1
Write each sum as a single logarithm. Assume that variables represent positive numbers. $$ \log _{5} 2+\log _{5} 7 $$
View solution