Problem 1
Question
\(\cdot\) The focal length of an \(f / 4\) camera lens is 300 \(\mathrm{mm}\) . (a) What is the aperture diameter of the lens? (b) If the correct exposure of a certain scene is \(\frac{1}{250}\) s at \(f / 4,\) what is the correct exposure at \(f / 8 ?\)
Step-by-Step Solution
Verified Answer
(a) 75 mm; (b) \(\frac{1}{62.5}\) s.
1Step 1: Understanding the Given Information
We start with an \(f/4\) camera lens which has a focal length of 300 mm. The \(f\)-number describes the aperture size in relation to the focal length. The correct exposure at \(f/4\) is given as \(\frac{1}{250}\) s, and we need to calculate the exposure time for \(f/8\).
2Step 2: Calculating the Aperture Diameter
The formula for the aperture diameter \(D\) in relation to the \(f\)-number \(N\) and the focal length \(f\) is \(D = \frac{f}{N}\). For \(f/4\), the aperture diameter is \(D = \frac{300\,\text{mm}}{4} = 75\,\text{mm}\).
3Step 3: Understand \(f/\) Number Changes
When the \(f\)-number changes from \(f/4\) to \(f/8\), the amount of light reaching the sensor decreases. Since \(f/8\) is two \(f\)-stops smaller than \(f/4\), the light is reduced by a factor of 4.
4Step 4: Calculating the Correct Exposure Time for \(f/8\)
To compensate for the reduced light at \(f/8\), we need to increase the exposure time by a factor of 4. The original exposure time at \(f/4\) is \(\frac{1}{250}\) s, so the new exposure time at \(f/8\) is \(4 \times \frac{1}{250} = \frac{1}{62.5}\) s.
Key Concepts
Aperture DiameterExposure Timef-stop
Aperture Diameter
The term "aperture diameter" refers to the opening through which light enters a camera lens. This opening plays a crucial role in determining the amount of light that reaches the camera's sensor. A larger aperture diameter lets in more light, which can be particularly useful in low-light conditions. The aperture diameter can be calculated using the formula:
\[ D = \frac{f}{N} \]where:
\[ D = \frac{f}{N} \]where:
- \(D\) is the aperture diameter.
- \(f\) is the focal length of the lens.
- \(N\) is the \(f\)-number.
Exposure Time
Exposure time, also known as shutter speed, is the duration for which the camera's shutter is open to allow light to hit the sensor. It plays a vital role in photography, affecting the brightness and clarity of the photo. In simpler terms, a longer exposure time means more light is captured, resulting in a brighter image.In the problem provided, the correct exposure time at \(f/4\) is given as \(\frac{1}{250}\) seconds. When changing to \(f/8\), we need to adjust the exposure time to account for the reduced light. Since \(f/8\) lets in less light than \(f/4\), we need to increase the exposure time by a factor of 4 (as two \(f\)-stops reduce the light). Therefore, the adjusted exposure time for \(f/8\) is \(\frac{1}{62.5}\) seconds, which helps maintain the necessary light for proper image exposure.
f-stop
The f-stop, or \(f\)-number, is a measure of the lens's aperture size relative to its focal length. It controls the depth of field in a photo and influences how much light enters through the lens. The \(f\)-stop scale is such that:
- Lower \(f\)-numbers (e.g., \(f/2\), \(f/4\)) have larger aperture openings and allow more light.
- Higher \(f\)-numbers (e.g., \(f/8\), \(f/16\)) reduce the aperture size and allow less light.
Other exercises in this chapter
Problem 2
\(\cdot\) Camera \(A\) has a lens with an aperture diameter of 8.00 \(\mathrm{mm}\) . It photographs an object, using the correct exposure time of \(\frac{1}{30
View solution Problem 3
\(\bullet\) (a) A small refracting telescope designed for individual use has an objective lens with a diameter of 6.00 \(\mathrm{cm}\) and a focal length of 1.3
View solution Problem 4
. A 135 mm telephoto lens for a 35 mm camera has \(f\) -stops that range from \(f / 2.8\) to \(f / 22\) . (a) What are the smallest and largest aperture diamete
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