Problem 1
Question
Calculate the value of the given inverse trigonometric function at the given point. $$ \arcsin (1) $$
Step-by-Step Solution
Verified Answer
The value of \( \arcsin(1) \) is \( \frac{\pi}{2} \).
1Step 1: Understand the Definition of Arcsine
The function \( \arcsin(x) \) is the inverse of the sine function, defined for \( -1 \leq x \leq 1 \). It returns the angle \( \theta \) in the interval \(-\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}\), where \( \sin(\theta) = x \).
2Step 2: Set the Expression
We need to solve \( \arcsin(1) = \theta \) such that \( \sin(\theta) = 1 \).
3Step 3: Determine the Angle
Within the interval \(-\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}\), the angle \( \theta \) for which \( \sin(\theta) = 1 \) is \( \frac{\pi}{2} \).
4Step 4: Conclusion
Thus, the value of \( \arcsin(1) \) is \( \frac{\pi}{2} \).
Key Concepts
Understanding ArcsineThe Sine Function ExplainedIntroduction to Trigonometry
Understanding Arcsine
The arcsine function, denoted as \( \arcsin(x) \), plays a key role in trigonometry. As the inverse of the sine function, arcsine "undoes" what the sine function does. Imagine both functions as two sides of a coin: one calculates the ratio of the opposite side to the hypotenuse in a right triangle, while the other deduces the angle from this ratio.
This function is defined only for \(-1 \leq x \leq 1\), which means its input, \(x\), must lie within this range. It returns angles in the interval \(-\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}\). If you input \(x = 1\), arcsine will help you find the angle whose sine is 1, staying within this specified range.
This function is defined only for \(-1 \leq x \leq 1\), which means its input, \(x\), must lie within this range. It returns angles in the interval \(-\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}\). If you input \(x = 1\), arcsine will help you find the angle whose sine is 1, staying within this specified range.
The Sine Function Explained
The sine function, often written as \( \sin(\theta) \), is fundamental in trigonometry. It relates to the sides of a right-angled triangle by giving the ratio of the length of the side opposite an angle \( \theta \) to the hypotenuse's length.
Sine values range from \(-1\) to \(1\). At an angle of \( \frac{\pi}{2} \) radians (or 90 degrees), \( \sin(\theta) = 1 \), representing its peak. Thus, when the arcsine function finds \( \arcsin(1) = \frac{\pi}{2} \), it is identifying the angle at which sine achieves its maximum value.
Important aspects of the sine function:
Sine values range from \(-1\) to \(1\). At an angle of \( \frac{\pi}{2} \) radians (or 90 degrees), \( \sin(\theta) = 1 \), representing its peak. Thus, when the arcsine function finds \( \arcsin(1) = \frac{\pi}{2} \), it is identifying the angle at which sine achieves its maximum value.
Important aspects of the sine function:
- Periodic: Repeats values every \(2\pi\) radians
- Odd Function: Symmetric around the origin
- Range: Only between \(-1\) and \(1\)
Introduction to Trigonometry
Trigonometry is the field of mathematics that examines the relationships in triangles. Primarily, it looks at right triangles to establish these relationships, using functions like sine, cosine, and tangent.
Key points about trigonometry include:
Key points about trigonometry include:
- Angle Measurement: Often uses radians, where \( \pi \) corresponds to 180 degrees.
- Functions: Involves sine, cosine, and tangent, alongside their inverses like arcsine.
- Applications: Helps in various fields such as physics, engineering, and architecture.
Other exercises in this chapter
Problem 1
In each of Exercises \(1-6, y\) is a function of \(x .\) Calculate the derivative of the given expression with respect to \(x\). (Your answer should contain the
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An expression for \(f(x)\) is given. Compute the first, second, and third derivatives of \(f(x)\) with respect to \(x\). \(5 x^{2}-6 x+7\)
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Calculate the derivative of the given expression with respect to \(x\). $$ \sin (3 x) $$
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