Problem 1
Question
Answer the following questions about the functions whose derivatives are given: \begin{equation}\begin{array}{l}{\text { a. What are the critical points of } f ?} \\ {\text { b. On what open intervals is } f \text { increasing or decreasing? }} \\ {\text { c. At what points, if any, does } f \text { assume local maximum and }} \\ \quad {\text { minimum values? }}\end{array}\end{equation} \begin{equation}f^{\prime}(x)=x(x-1)\end{equation}
Step-by-Step Solution
Verified Answer
Critical points are at \(x=0\) and \(x=1\). \(f\) increases on \((-\infty, 0)\) and \((1, \infty)\), and decreases on \((0, 1)\). Local maximum at \(x=0\) and minimum at \(x=1\).
1Step 1: Find Critical Points
To find the critical points of the function, set the derivative \(f'(x) = x(x-1)\) equal to zero. Solve the equation \(x(x-1) = 0\), which gives the critical points as \(x = 0\) and \(x = 1\).
2Step 2: Determine Intervals
Use the critical points to determine intervals by setting x-values around the critical points. The intervals will be \((-\infty, 0)\), \((0, 1)\), and \((1, \infty)\).
3Step 3: Test Increasing or Decreasing Nature
For each interval, select a test point not equal to the critical points and substitute it into the derivative \(f'(x) = x(x-1)\) to determine sign. - For \((-\infty, 0)\), choose \(x = -1\), and \(f'(-1) = (-1)((-1)-1) = 2\), so it is increasing.- For \((0, 1)\), choose \(x = \frac{1}{2}\), and \(f'(\frac{1}{2}) = (\frac{1}{2})(\frac{1}{2}-1) = -\frac{1}{4}\), so it is decreasing.- For \((1, \infty)\), choose \(x = 2\), and \(f'(2) = 2(2-1) = 2\), so it is increasing.
4Step 4: Identify Local Extrema
Use the first derivative test by analyzing the change of sign of \(f'(x)\) around the critical points.- At \(x = 0\), \(f'(x)\) changes from positive to negative, so \(x = 0\) is a local maximum.- At \(x = 1\), \(f'(x)\) changes from negative to positive, so \(x = 1\) is a local minimum.
Key Concepts
DerivativesIncreasing and Decreasing IntervalsLocal ExtremaFirst Derivative Test
Derivatives
In calculus, a derivative represents the rate at which a function changes with respect to one of its variables. Essentially, the derivative of a function at a point gives you the slope of the tangent line to the function's graph at that point. This concept is crucial for understanding many behaviors of functions.
- The derivative of a function can provide information on the function's growth and rate of change.
- For a given function \( f(x) \), the derivative \( f'(x) \) is generally found using differentiation rules like the power rule, product rule, quotient rule, and chain rule.
- The critical points of a function, where the derivative equals zero or is undefined, are key in analyzing the function's behavior.
Increasing and Decreasing Intervals
Identifying where a function is increasing or decreasing is fundamental for understanding the overall trend of the function. This behavior is determined by examining the sign of the derivative.
- A function is increasing on an interval if its derivative is positive across that interval.
- Conversely, a function is decreasing on an interval if the derivative is negative across that interval.
- Critical points often serve as boundary markers that separate increasing and decreasing behaviors.
Local Extrema
Local extrema of a function, which include local minimums and maximums, are points where the function values are the least or greatest, respectively, in a small neighborhood. Discovering these points is essential as they help in sketching the graph of a function.
- A local maximum occurs at a critical point if the function changes from increasing to decreasing.
- A local minimum happens where the function shifts from decreasing to increasing.
- Analyzing the sign change of the derivative around critical points helps identify these extrema.
First Derivative Test
The first derivative test is a straightforward method used to classify the local extrema of a function. This test uses the derivative's sign change over critical points to determine where local minimums and maximums occur.
- If the derivative changes from positive to negative at a critical point, the point is a local maximum.
- If the derivative switches from negative to positive, the point is a local minimum.
- No change in sign might indicate a point of inflection rather than an extrema.
Other exercises in this chapter
Problem 1
Minimizing perimeter for a rectangle whose area is \(16 \mathrm{in}^{2},\) and what are its dimensions?
View solution Problem 1
Identify the inflection points and local maxima and minima of the functions graphed in Exercises \(1-8 .\) Identify the intervals on which the functions are con
View solution Problem 1
Find the value or values of \(c\) that satisfy the equation $$\frac{f(b)-f(a)}{b-a}=f^{\prime}(c)$$ in the conclusion of the Mean Value Theorem for the function
View solution Problem 2
In Exercises \(1-16,\) find an antiderivative for each function. Do as many as you can mentally. Check your answers by differentiation. $$\text { a. }6 x \quad
View solution