Problem 1
Question
A rod of length \(L\) coincides with the interval \([0, L]\) on the \(x\) -axis. Set up the boundary-value problem for the temperature \(u(x, t)\) The left end is held at temperature zero, and the right end is insulated. The initial temperature is \(f(x)\) throughout.
Step-by-Step Solution
Verified Answer
The problem is set by the heat equation with given boundary and initial conditions.
1Step 1: Identify the Problem
We need to set up a boundary-value problem involving the temperature distribution along a rod that has specified conditions at its ends. The rod lies on the interval \([0, L]\) of the \(x\)-axis.
2Step 2: Define the Heat Equation
The temperature distribution in the rod is governed by the heat equation:\[\frac{\partial u}{\partial t} = k \frac{\partial^2 u}{\partial x^2}\]where \(u(x, t)\) represents the temperature at position \(x\) and time \(t\), and \(k\) is the thermal diffusivity.
3Step 3: Apply Boundary Conditions
The boundary conditions are as follows:- The left end \((x=0)\) is held at temperature zero: \(u(0, t) = 0\) for all \(t > 0\).- The right end \((x=L)\) is insulated, implying \(\frac{\partial u}{\partial x}(L, t) = 0\) for all \(t > 0\).
4Step 4: Set Initial Condition
The initial temperature distribution is given by \(u(x, 0) = f(x)\) for all \(x\) in \([0, L]\). This represents the temperature at time \(t=0\).
5Step 5: Formulate the Boundary-Value Problem
Putting it all together, the boundary-value problem is:Solve \(\frac{\partial u}{\partial t} = k \frac{\partial^2 u}{\partial x^2}\) with:1. Boundary conditions: \(u(0, t) = 0\) and \(\frac{\partial u}{\partial x}(L, t) = 0\).2. Initial condition: \(u(x, 0) = f(x)\).
Key Concepts
Heat EquationThermal DiffusivityInsulated Boundary ConditionTemperature Distribution
Heat Equation
The heat equation is a fundamental concept used to describe how temperature changes within a material over time. Imagine the rod as a long, narrow space where heat spreads.* The equation \[ \frac{\partial u}{\partial t} = k \frac{\partial^2 u}{\partial x^2} \] helps us understand the temperature, represented by \(u(x, t)\), at any point \(x\) along the rod and at any time \(t\).* Here, \( \frac{\partial u}{\partial t} \) represents how temperature changes over time, while \( \frac{\partial^2 u}{\partial x^2} \) shows how it changes over space, specifically along the rod.* This equation assumes a constant property called thermal diffusivity, \(k\), which we will cover next. It's essential for predicting how quickly the heat spreads throughout the rod.
Thermal Diffusivity
Thermal diffusivity, denoted as \(k\), is a material property that helps us predict how heat diffuses through a substance. In simple words, it's a measure of how quickly or slowly temperature spreads within the rod.* A higher value of \(k\) means that temperature changes more rapidly with time as it spreads farther along the rod.* Conversely, a lower \(k\) indicates that heat takes longer to move, leading to slower temperature changes.Understanding \(k\) is crucial when solving the heat equation, as it directly influences how your model predicts temperature evolution within the material.
Insulated Boundary Condition
An insulated boundary condition is a scenario where no heat crosses the boundary of a system — in our case, the end of the rod.* For the rod problem, one end is kept at zero temperature, effectively held steady by external conditions, while the other end (\(x = L\)) is insulated.* The insulated nature is mathematically expressed as \[ \frac{\partial u}{\partial x}(L, t) = 0 \] indicating no temperature change, meaning heat does not escape the rod at this end.This condition helps maintain a stable system and simplifies calculations, as it leads to a specific solution pattern over the rod's length.
Temperature Distribution
Temperature distribution is all about understanding where and how the heat spreads over the length of the rod at any given time.* Initially, the temperature is distributed along the rod based on a known function \(u(x, 0) = f(x)\) provided for all positions \(x\) from 0 to \(L\).* Over time, influenced by the heat equation and boundary conditions, this distribution evolves.Visualizing this distribution helps comprehend how certain areas of the rod will warm up, cool down, or stabilize, crucial for practical applications, like designing systems for efficient heat management or safety measures in engineering projects.
Other exercises in this chapter
Problem 1
In Problems \(1-10\), solve Laplace's equation (1) for a rectangular plate subject to the given boundary conditions. \(u(0, y)=0, u(a, y)=0\) \(u(x, 0)=0, u(x,
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In Problems \(1-6\), solve the wave equation (1) subject to the given conditions. \(u(0, t)=0, \quad u(L, t)=0, \quad t>0\) \(u(x, 0)=\frac{1}{4} x(L-x),\left.\
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In Problems, solve the heat equation (1) subject to the given conditions. Assume a rod of length \(L\). $$ \begin{aligned} &u(0, t)=0, u(L, t)=0 \\ &u(x, 0)=\le
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In Problems 1-16, use separation of variables to find, if possible, product solutions for the given partial differential equation. $$ \frac{\partial u}{\partial
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