Problem 1
Question
A particle of mass \(5 \mathrm{~kg}\) is pulled along a smooth horizontal surface by a horizontal string. The acceleration of the particle is \(10 \mathrm{~ms}^{-2}\). The tension in the string is: (a) \(2 \mathrm{~N}\) (b) \(50 \mathrm{~N}\) (c) \(5 \mathrm{~N}\) (d) \(15 \mathrm{~N}\) (e) \(10 \mathrm{~N}\).
Step-by-Step Solution
Verified Answer
The tension in the string is 50 N (option b).
1Step 1: Understand the Given Information
A particle with mass (m) of 5 kg is pulled on a smooth horizontal surface, meaning there is no friction. The acceleration (a) of the particle is given as 10 m/s². The goal is to find the tension (T) in the string.
2Step 2: Use Newton’s Second Law
Newton’s second law states that the force (F) acting on an object is the product of its mass and acceleration. The formula is: \[F = m \times a\]. Since the tension in the string (T) is the force causing the particle to accelerate, we substitute T for F.
3Step 3: Substitute the Known Values
Substitute the mass (m = 5 kg) and the acceleration (a = 10 m/s²) into the formula: \[T = 5 \times 10\].
4Step 4: Calculate the Tension
Now calculate the value: \[T = 50\]. Thus, the tension in the string is 50 N.
5Step 5: Select the Correct Answer
Among the given options, the correct option is (b) 50 N.
Key Concepts
Force CalculationMass and AccelerationTension in Physics Problems
Force Calculation
When dealing with physics problems that involve forces, understanding how to calculate force is crucial. Newton's Second Law provides a simple yet powerful equation to do this: \[ F = m \times a \]In this formula,
- F represents the force applied to an object,
- m stands for mass, and
- a is the acceleration.
Mass and Acceleration
Understanding the relationship between mass and acceleration is key to comprehending Newton's Second Law. In the formula \[ F = m \times a \]mass (m) and acceleration (a) are directly proportional to the force (F). This means that:
- If you increase the mass while keeping acceleration constant, the force will increase proportionally.
- Similarly, if you increase the acceleration while keeping the mass constant, the force will also increase proportionally.
Tension in Physics Problems
Tension is a common force that appears in many physics problems, especially those involving ropes, strings, or cables that pull or hang objects. In our exercise, tension is the force that pulls the particle and causes it to accelerate. To find the tension in the string, we used Newton's Second Law.Tension force often involves the following steps:
- Identify the forces acting on the object: In our problem, the only force considered was the tension in the string pulling the particle horizontally.
- Apply Newton’s Second Law: We write the equation of motion using the known values of mass and acceleration.
- Solve for tension: By substituting the known quantities into the equation, we calculated that tension, T, is 50 N.
Other exercises in this chapter
Problem 2
A particle of mass \(3 \mathrm{~kg}\) slides down a smooth plane inclined at arcsin \(\frac{1}{3}\) to the horizontal. The acceleration of the particle is: (a)
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A block of mass \(10 \mathrm{~kg}\) rests on the floor of a lift which is accelerating upwards at \(4 \mathrm{~ms}^{-2}\). The reaction of the floor of the lift
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Two particles of mass \(3 \mathrm{~kg}\) and \(5 \mathrm{~kg}\) are connected by a light inextensible string passing over a smooth pulley which is fixed to the
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