Problem 1
Question
A circular area with a radius of 6.50 \(\mathrm{cm}\) lies in the \(x\) -y plane. What is the magnitude of the magnetic flux through this circle due to a uniform magnetic field \(B=0.230 \mathrm{T}\) that points (a) in the \(+z\) direction? (b) at an angle of \(53.1^{\circ}\) from the \(+z\) direction? (c) in the \(+y\) direction?
Step-by-Step Solution
Verified Answer
(a) 0.00306 Wb, (b) 0.00184 Wb, (c) 0 Wb.
1Step 1: Calculate Area of the Circle
First, calculate the area of the circular area. The formula for the area of a circle is \(A = \pi r^2\), where \(r\) is the radius of the circle. Here, \(r = 6.50 \, \mathrm{cm} = 0.065 \, \mathrm{m}\). Substituting, we have:\[A = \pi (0.065)^2 \approx 0.0133 \, \mathrm{m^2}\]
2Step 2: Calculate Magnetic Flux for (a) - Field in +z Direction
The magnetic flux \(\Phi\) for a magnetic field \(B\) perpendicular to the surface (along the normal) is given by \(\Phi = B \cdot A\). Since the magnetic field is in the \(+z\) direction and the circle is in the \(x-y\) plane, the angle \(\theta\) between them is \(0^\circ\). Thus, \[ \Phi = B \cdot A \cdot \cos(0^\circ) = 0.230 \, \mathrm{T} \times 0.0133 \, \mathrm{m^2} \approx 0.00306 \, \mathrm{Wb}\]
3Step 3: Calculate Magnetic Flux for (b) - Field at 53.1° from +z Direction
In this case, the angle \(\theta\) between the magnetic field and the normal to the circle is \(53.1^\circ\). Thus, the magnetic flux is calculated as:\[ \Phi = B \cdot A \cdot \cos(53.1^\circ) = 0.230 \, \mathrm{T} \times 0.0133 \, \mathrm{m^2} \times \cos(53.1^\circ) \approx 0.00184 \, \mathrm{Wb}\]
4Step 4: Calculate Magnetic Flux for (c) - Field in +y Direction
When the magnetic field is in the \(+y\) direction, it is perpendicular to the normal of the circular area, as the normal is in the \(+z\) direction. Therefore, the angle \(\theta = 90^\circ\). The magnetic flux is:\[ \Phi = B \cdot A \cdot \cos(90^\circ) = 0.230 \, \mathrm{T} \times 0.0133 \, \mathrm{m^2} \times 0 = 0 \, \mathrm{Wb} \]
Key Concepts
Magnetic FieldCircular AreaAngle of Inclination
Magnetic Field
The concept of the magnetic field is central in understanding how forces affect charged particles in motion. A magnetic field represents a region where a magnetic force can be detected. It is often generated by moving electric charges or magnetic dipoles and can be uniform or vary in strength and direction.
Magnetic field lines provide a way to visualize a magnetic field. They start from the north pole and end at the south pole of a magnet. The direction of these lines indicates the direction of the magnetic force a north pole of a magnet would experience. The density of these lines reflects the strength of the magnetic field: the closer the lines, the stronger the field.
Magnetic field lines provide a way to visualize a magnetic field. They start from the north pole and end at the south pole of a magnet. The direction of these lines indicates the direction of the magnetic force a north pole of a magnet would experience. The density of these lines reflects the strength of the magnetic field: the closer the lines, the stronger the field.
- The magnetic field can be measured in units called Tesla (T).
- A uniform magnetic field means the magnetic lines are parallel and equally spaced.
Circular Area
A circular area is simply the two-dimensional space enclosed by a circle. The size of this area plays an important role when calculating magnetic flux. The larger the area, the more flux it can capture, assuming other things like the magnetic field strength and orientation remain constant.
The formula for determining the area of a circle is given by:\[A = \pi r^2\]where \(r\) is the radius. If it's essential to work in consistent units, remember to convert all measurements to meters or the standard unit you're using.
The formula for determining the area of a circle is given by:\[A = \pi r^2\]where \(r\) is the radius. If it's essential to work in consistent units, remember to convert all measurements to meters or the standard unit you're using.
- Area is measured in square meters \( \mathrm{m^2} \) in physics.
- A precise measurement is crucial for accurate calculations.
Angle of Inclination
The angle of inclination, expressed as \( \theta \), is the angle between the magnetic field line and the normal (perpendicular) to the surface of the circular area. This angle is crucial because it affects the magnitude of the magnetic flux.
Magnetic flux \( \Phi \) through a surface is calculated by the formula:\[\Phi = B \cdot A \cdot \cos(\theta)\]where \(B\) is the magnetic field strength, \(A\) is the area, and \(\theta\) is this angle of inclination.
Magnetic flux \( \Phi \) through a surface is calculated by the formula:\[\Phi = B \cdot A \cdot \cos(\theta)\]where \(B\) is the magnetic field strength, \(A\) is the area, and \(\theta\) is this angle of inclination.
- When the field is perpendicular to the surface (\(\theta = 0^\circ \)), \(\cos(0^\circ) = 1\), indicating maximum flux.
- When parallel (\(\theta = 90^\circ\)), \(\cos(90^\circ) = 0\), meaning no flux passes through.
Other exercises in this chapter
Problem 4
A single loop of wire with an area of 0.0900 \(\mathrm{m}^{2}\) is in a uniform magnetic field that has an initial value of 3.80 \(\mathrm{T}\) , is perpendicul
View solution Problem 5
A coil of wire with 200 circular turns of radius 3.00 \(\mathrm{cm}\) is in a uniform magnetic field along the axis of the coil. The coil has \(R=40.0 \Omega\)
View solution Problem 6
In a physics laboratory experiment, a coil with 200 turns enclosing an area of 12 \(\mathrm{cm}^{2}\) is rotated from a position where its plane is perpendicula
View solution