The solution o the equation arex≈ 0.54, x≈ 1.68 , x≈ -2.21

In Problems 5–16, use a graphing utility to approximate the real solutions, if any, of each equation rounded to two decimal places. All solutions lie between - 10 and 10. - Precalculus Enhanced with Graphing Utilities

In Problems 5–16, use a graphing utility to approximate the real solutions, if any, of each equation rounded to two decimal places. All solutions lie between - 10 and 10.

$x^{3} - 4 x + 2 = 0$

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Answer

The solution o the equation are $x \approx 0.54, x \approx 1.68, x \approx - 2.21$

1Step 1. Given equation

$x^{3} - 4 x + 2 = 0$

2Step 2. Draw graph of this equation and find the x-intercept

X-intercepts are $x \approx 0.53918 \dots, x \approx 1.67513 \dots, x \approx - 2.21431 \dots$