Q. 292 - Intermediate Algebra

Question

In the following exercises, solve.
$\sqrt[3]{4x-1}=3$

Step-by-Step Solution

Answer

The solution of the given equation is $x=7$.

Step 1. Given information.

The given equation is:

$\sqrt[3]{4x-1}=3$

Step 2. Solve the equation.

Take cube on both sides.

$\begin{array}{rcl}(\sqrt[3]{4x-1}{)}^3& =& (3{)}^3\\ 4x-1& =& 27\\ 4x& =& 27+1\\ 4x& =& 28\end{array}$

Divide both sides by 4.

$\begin{array}{rcl}\frac{4x}{4}& =& \frac{28}{4}\\ x& =& 7\end{array}$

Step 3. Conclusion.

The solution of the given equation is $x=7$.