61 PE
Question
Using approximate values, calculate the slope of the curve in Figure 2.62 to verify that the velocity at t= 30 sec is 0.238 m/s. Assume all values are known to 3 significant figures
Step-by-Step Solution
VerifiedThe velocity is approximately the value 0.233 m/s
To analyses movement, motion graphs can be employed.
The mathematical approaches and graphical solutions for determining motion equations are the same.
The slope of a graph of displacement x vs. time t represents velocity v.
The inclination of a graph of velocity v vs. time t is called acceleration.
Average velocity, instantaneous velocity, and acceleration can all be calculated using graphs.
Here if we carefully look into the figure, in your text book let’s take any two points on the line
Coordinate \(\left( {30,9} \right)\) and \(\left( {60,16} \right)\)
Slop of the line will be
\[\begin{array}{l}m = \frac{{{y_2} - {y_1}}}{{{x_2} - {x_2}}}\\Here\,the\,coordinates\,are\,(30,9)\,\,\,and\,\,\,(60,16)\\m = \frac{{16 - 9}}{{60 - 30}}\\m = 0.233\,m/s\end{array}\]
Hence the velocity is approximately to the value \[0.233 m/s\]