6-35 a
Question
Follow the flow of electrons indicated by the curved arrows in each of the following polar reactions, and predict the products that result:
Step-by-Step Solution
Verified Answer
(a)
Curved arrow representation
1Attack of hydroxide ion
The hydroxide ion attacks the hydrogen of the alcohol. This results in deprotonation to form water and an alkoxide. Next, the bonding pair of electrons flow down to the oxygen that had its hydrogen removed.
2Formation of carbon-carbon double bond
These bonding pairs of electrons form a carbon-oxygen double bond. This new bond forces the methoxy group to leave as methoxide. The leaving group is negatively charged because wherever the arrow stops is where the charge ends up. Thus, the curved arrow representation is as shown:
Curved arrow representation
Other exercises in this chapter
6-33c
For each reaction below identify the electrophile and the nucleophile(a) (b) (c)
View solution 6-34
Add curved arrows to the following polar reactions to indicate the flow of electrons in each:(a) (b)
View solution 6-35b
Follow the flow of electrons indicated by the curved arrows in each of the following polar reactions, and predict the products that result:
View solution 6-35c
Follow the flow of electrons indicated by the curved arrows in each of the following polar reactions, and predict the products that result:
View solution