How many NH3 molecules are produced by the reaction of 4 mol of Ca(OH)2 according to the following reaction\({\left( {N{H_4}} \right)_2}S{O_4} + Ca{\left( {OH} \right)_2} \to 2N{H_3} + CaS{O_4} + 2{H_2}O\)

4.8 x 1024 molecules of NH3 are produced.

4.9 CYL - Chemistry (OpenStax)

How many NH₃ molecules are produced by the reaction of 4 mol of Ca(OH)₂ according to the following reaction

\({\left( {N{H_4}} \right)_2}S{O_4} + Ca{\left( {OH} \right)_2} \to 2N{H_3} + CaS{O_4} + 2{H_2}O\)

Verified

Answer

4.8 x 10²⁴ molecules of NH₃ are produced.

1Determining the number of moles of NH 3

\({\left( {N{H_4}} \right)_2}S{O_4} + Ca{\left( {OH} \right)_2} \to 2N{H_3} + CaS{O_4} + 2{H_2}O\)

From the given balanced reaction, we can see that

1 mol of Ca (OH)₂ produces 2 mol of NH₃

So, 4 mol of Ca (OH)₂ will produce 8 mol of NH₃

2Determining the number of molecules of NH 3

1 mol of NH₃ contains 6.022 x 10²³ molecules of NH₃

So, 8 mol of NH₃ will contain

8 x 6.022 x 10²³= 4.8 x 10²⁴ molecules of NH₃