Q. 253 - Intermediate Algebra

Question

In the following exercises, find the product of${\left(m^3-8n\right)}^2$.

Step-by-Step Solution

Answer

The product of ${\left(m^3-8n\right)}^2$ is $m^6-16m^{3}n+64n^2$

Step 1. Given Information.

The given expression is ${\left(m^3-8n\right)}^2$.

Step 2. Solve for the multiplication of given expression.

Multiply the expression ${\left(m^3-8n\right)}^2$.

$$\begin{gathered} {\left(m^3-8n\right)}^2={\left(m^3\right)}^2-2m^3·\hspace{0.17em}8n+{\left(8n\right)}^2 \\ {\left(m^3\right)}^2-2m^3·\hspace{0.17em}8n+{\left(8n\right)}^2=m^6-16m^{3}n+64n^2 \end{gathered}$$